Answer:
A. Measure of angle 2 + measure of angle 3
Step-by-step explanation:
Because angle 4 is an exterior angle of given triangle which will be equal to the Measure of angle 2 + measure of angle 3
Answer:
He set the compass on a, with the width slightly wider than the distance to o and drew an arc above and below o. He then set the compass on b, without changing the width on the compass and did the same thing. True
He drew a line through where the arc pairs intersected and then labeled the points where this line crossed the top and bottom of the original circle. True
He set the compass on o, with the width slightly wider than the distance to b, and he drew a slightly larger circle around the original circle. False
He used the points that were marked along the circumference of the original circle as the vertices for the square. True
Step-by-step explanation:
Performance matters test perhaps?
Answer:
(A) 6x³+8x² + 4x - 4, but only if my change is correct to <u>6x³5x² - 2</u> is correct.
Step-by-step explanation:
<u>Is "g(x) = 6x³5x² - 2" meant to be g(x) = 6x³-5x² - 2?</u>
<u>If so,</u> (f+g)(x) = 3x² + 4x - 6 - (6x³-5x² - 2)
(f+g)(x) = 3x² + 4x - 6 - 6x³+5x² + 2
(f+g)(x) = 6x³+8x² + 4x - 4
(A)
Answer:
q = 0
Step-by-step explanation:
The ratio of highest-degree terms is (6x^5)/(x^9) = 6/x^4. This approaches zero when x gets large, either positive or negative.
The horizontal asymptote is q = 0.
