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Eddi Din [679]
3 years ago
15

Alan induces beth to enter into a contract for the purchase of a chef's burger house restaurant. alan knowingly misrepresents a

number of material features about the restaurant and the business. when beth discovers the truth, she can rescind the contract on the basis o
Business
1 answer:
evablogger [386]3 years ago
6 0

Answer: Fraud

Explanation: Contracts are legally binding and thus cannot be rescinded (cancelled) easily. The only way a contract may be rescinded is if evidence exists that undue influence (forcing someone into the contract) or fraud took place. In terms of fraud if a person is induced into a contract by material misrepresentation, then the person who was induced into the contract may rescind the contract.

Beth was induced into the contract by Alan. Because Alan knowingly misrepresented material features about the business to Beth, this is a form of fraud on Alan's part. Beth is thus allowed to rescind the contract.

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"A high-ranking officer of ABC Corporation owns 10,000 shares of ABC Corporation control stock that she wishes to sell under the
LuckyWell [14K]

Answer: $9,000

Explanation:

Rule 144 is a regulation that governs the trading of restricted, unregistered, and control securities and is enforceable by the SEC.

Under the rule, the person, as an officer of the ABC Corporation is limited to selling the higher of 1% of the Outstanding stock the company has or the average weekly trading volume over the preceding 4 weeks.

1% of the outstanding 900,000 shares is;

= 1% * 900,000

= 9,000 shares

This is higher than the average weekly trading volume over the preceding 4 weeks so this is the maximum permitted sales figure.

3 0
3 years ago
O'Brien Ltd.'s outstanding bonds have a $1,000 par value, and they mature in 25 years. Their nominal yield to maturity is 9.25%,
kozerog [31]

Answer:

8.99%

Explanation:

For this question we use the PMT function that is presented on the excel spreadsheet. Kindly find it below:

Given that,  

Present value = $975

Future value = $1,000

Rate of interest = 9.25%  ÷ 2 = 4.625%

NPER = 25 years × 2 = 50 years

The formula is shown below:

= PMT(Rate,NPER,-PV,FV,type)

The present value come in negative

So, after solving this, the PMT is $44.96

Now the annual PMT is

= $44.96 × 2

= $89.92

So, the coupon interest rate is

= $89.92 ÷ $1,000

= 8.99%

4 0
3 years ago
_____ power is a function of the amount of knowledge one possesses relative to the rest of the members of a group
shutvik [7]
Expert power is a function of the amount of knowledge one possesses relative to the rest of the members of a group.
7 0
3 years ago
Bonds that have interest coupons attached to their certificates, which the bondholders present to a bank or broker for collectio
kiruha [24]
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3 0
2 years ago
Agan Interior Design provides home and office decorating assistance to its customers. In normal operation, an average of 2.5 cus
Phantasy [73]

Answer:

A) Single-server single-phase model (M/M/1).

\lambda=2.5 \,customers/hour\\\\\mu=6\,customers/hour

B) The goal is not met, as the average time waiting for service is 5.56 minutes.

C) The new mean service rate is 7.5 customers/hour.

In this case, the average time waiting for service is 4 minutes, so the goal is met.

Explanation:

A) This situation can be modeled as a single-server single-phase model (M/M/1).

The mean arrival rate is 2.5 customers per hour.

\lambda=2.5 \,customer/h

The mean service rate is 6 customers per hour, calculated as:

\mu=\frac{60\, min/h}{10 \,min/customer}=6\, customer/h

B) The average waiting time for a customer can be expressed as:

W_q=\frac{\lambda}{\mu}\frac{1}{\mu-\lambda}  =\frac{2.5}{6}\frac{1}{6-2.5} =0.417*0.222=0.093\,hours\\\\W_q=0.093\,hours*(60min/h)=5.56 \,min

The average waiting time is 5.56 minutes, so it is more than the goal of 5 minutes.

C) If the average time spent per customer to 8 minutes, the mean service rate becomes

\mu=\frac{60\, min/h}{8 \,min/customer}=7.5\, customer/h

An the average waiting time for the service now becomes:

W_q=\frac{\lambda}{\mu}\frac{1}{\mu-\lambda}  =\frac{2.5}{7.5}\frac{1}{7.5-2.5} =0.333*0.2=0.067\,hours\\\\W_q=0.067\,hours*(60min/h)=4 \,min

The average time is now 4 minutes, so the goal is achieved.

6 0
3 years ago
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