1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
neonofarm [45]
3 years ago
14

Find the surface area of the cone with a diameter of centimeters and a slant height of millimeters

Mathematics
1 answer:
defon3 years ago
5 0

Answer:

The first step in finding the surface area of a cone is to measure the radius of the circle part of. Therefore, the total surface area of the cone is 83.17cm2.

Step-by-step explanation:

You might be interested in
An angle measures 36.8° more than the measure of its complementary angle. What is
grandymaker [24]

Answer:

og angle: 126.8

complementary angle: 53.2

og angle mirror (if any): 126.8

complementary angle mirror (if any): 53.2

5 0
2 years ago
You have 400 cards stored 3/5 of them are from family. 1/4 of them are from friends. The rest you made. How many cards did you m
omeli [17]
You made 3/20 of the 400 cards, which is 60 cards.
5 0
2 years ago
Calculus 3 help please.​
Reptile [31]

I assume each path C is oriented positively/counterclockwise.

(a) Parameterize C by

\begin{cases} x(t) = 4\cos(t) \\ y(t) = 4\sin(t)\end{cases} \implies \begin{cases} x'(t) = -4\sin(t) \\ y'(t) = 4\cos(t) \end{cases}

with -\frac\pi2\le t\le\frac\pi2. Then the line element is

ds = \sqrt{x'(t)^2 + y'(t)^2} \, dt = \sqrt{16(\sin^2(t)+\cos^2(t))} \, dt = 4\,dt

and the integral reduces to

\displaystyle \int_C xy^4 \, ds = \int_{-\pi/2}^{\pi/2} (4\cos(t)) (4\sin(t))^4 (4\,dt) = 4^6 \int_{-\pi/2}^{\pi/2} \cos(t) \sin^4(t) \, dt

The integrand is symmetric about t=0, so

\displaystyle 4^6 \int_{-\pi/2}^{\pi/2} \cos(t) \sin^4(t) \, dt = 2^{13} \int_0^{\pi/2} \cos(t) \sin^4(t) \,dt

Substitute u=\sin(t) and du=\cos(t)\,dt. Then we get

\displaystyle 2^{13} \int_0^{\pi/2} \cos(t) \sin^4(t) \, dt = 2^{13} \int_0^1 u^4 \, du = \frac{2^{13}}5 (1^5 - 0^5) = \boxed{\frac{8192}5}

(b) Parameterize C by

\begin{cases} x(t) = 2(1-t) + 5t = 3t - 2 \\ y(t) = 0(1-t) + 4t = 4t \end{cases} \implies \begin{cases} x'(t) = 3 \\ y'(t) = 4 \end{cases}

with 0\le t\le1. Then

ds = \sqrt{3^2+4^2} \, dt = 5\,dt

and

\displaystyle \int_C x e^y \, ds = \int_0^1 (3t-2) e^{4t} (5\,dt) = 5 \int_0^1 (3t - 2) e^{4t} \, dt

Integrate by parts with

u = 3t-2 \implies du = 3\,dt \\\\ dv = e^{4t} \, dt \implies v = \frac14 e^{4t}

\displaystyle \int u\,dv = uv - \int v\,du

\implies \displaystyle 5 \int_0^1 (3t-2) e^{4t} \,dt = \frac54 (3t-2) e^{4t} \bigg|_{t=0}^{t=1} - \frac{15}4 \int_0^1 e^{4t} \,dt \\\\ ~~~~~~~~ = \frac54 (e^4 + 2) - \frac{15}{16} e^{4t} \bigg|_{t=0}^{t=1} \\\\ ~~~~~~~~ = \frac54 (e^4 + 2) - \frac{15}{16} (e^4 - 1) = \boxed{\frac{5e^4 + 55}{16}}

(c) Parameterize C by

\begin{cases} x(t) = 3(1-t)+t = -2t+3 \\ y(t) = (1-t)+2t = t+1 \\ z(t) = 2(1-t)+5t = 3t+2 \end{cases} \implies \begin{cases} x'(t) = -2 \\ y'(t) = 1 \\ z'(t) = 3 \end{cases}

with 0\le t\le1. Then

ds = \sqrt{(-2)^2 + 1^2 + 3^2} \, dt = \sqrt{14} \, dt

and

\displaystyle \int_C y^2 z \, ds = \int_0^1 (t+1)^2 (3t+2) \left(\sqrt{14}\,ds\right) \\\\ ~~~~~~~~ = \sqrt{14} \int_0^1 \left(3t^3 + 8t^2 + 7t + 2\right) \, dt \\\\ ~~~~~~~~ = \sqrt{14} \left(\frac34 t^4 + \frac83 t^3 + \frac72 t^2 + 2t\right) \bigg|_{t=0}^{t=1} \\\\ ~~~~~~~~ = \sqrt{14} \left(\frac34 + \frac83 + \frac72 + 2\right) = \boxed{\frac{107\sqrt{14}}{12}}

8 0
1 year ago
Can someone please help me with 44. And 45?
Angelina_Jolie [31]

Problem 44

The term "bisect" means "cut in half".

Since BD bisects angle ABC, this means the smaller angles ABD and DBC are congruent.

angle ABD = angle DBC

x+15 = 4x-45

15+45 = 4x-x

60 = 3x

3x = 60

x = 60/3

x = 20

<h3>Answer:  x = 20</h3>

========================================================

Problem 45

We use the same idea as the previous problem

angle ABD = angle DBC

2x+35 = 5x-22

35+22 = 5x-2x

57 = 3x

3x = 57

x = 57/3

x = 19

<h3>Answer: x = 19</h3>
6 0
2 years ago
Read 2 more answers
Use the triangle formed by the vertices L(—3, 4), A(O, 5) and D(2, l). AL' A'D' is a triangle formed by using the transformation
weqwewe [10]

Answer:

figuring it out now

Step-by-step explanation:

6 0
3 years ago
Other questions:
  • What is number 2,3,4,5
    10·1 answer
  • The doubling time of a population of flies is 5 hours. By what factor does the population increase in 24 hours? By what factor d
    9·1 answer
  • Un triángulo isósceles ,la altura al lado desigual mide 1 cm mas que longitud de ese lado . Calcula el valor de dicha altura sab
    13·1 answer
  • 15 of 20: Select the best answer for the question.<br>reduce fraction
    10·1 answer
  • Lake Chad in Africa had a surface area of about 10,000 square miles in 1963. Because of climate changes and increased water usag
    7·1 answer
  • HELP PLZ
    5·1 answer
  • The hypotenuse of right triangle is 52 centimeters long. The difference between the other two sides is 28 centimeters.
    7·1 answer
  • PLEASE HURRY!!!!!!!!!!1
    13·2 answers
  • Alicia and Leah are making cookies for a fundraiser.
    6·1 answer
  • If a dozen exercise books cost 144, what will 14 of the same books cost
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!