Answer:
3X/20 (option a) of the pastries submitted by Rashid and Mikhail were brushed with butter
Step-by-step explanation:
Rashid pastries (R)
Mikhail pastries (M)
Rashid and Mikhail submitted a total of x pastries
R+M=x (I)
Rashid made 2/3 as many pastries as Mikhail
(2/3)*R=M (II)
Using II in I
R+(2/3)*R=x
(5/3)*R = x
R=(3/5)*x (III)
Using III in I
(3/5)*x+M=x
M=x-(3/5)*x
M=(2/5)*x (IV)
Mikhail filo dough (MF)
Mikhail shortcrust dough (MS)
Rashid filo dough (RF)
Rashid shortcrust dough (RS)
Mikhail used filo dough for all of his pastries
MF=M
MS=0
Rashid used shortcrust dough for all of his pastries
RS=R
RF=0
Filo dough (FD)
FD=RF+MF=0+MF=MF=M (V)
5/8 of the filo dough pastries were brushed with olive oil
pastries brushed with olive oil (OI)
(5/8)*FD=OI
Using V
(5/8)*M=OI
Using IV
(5/8)*(2/5)*x=OI
(1/4)*x=OI (VI)
pastries brushed with butter (B)
Pastries made out of filo dough are brushed with either olive oil or butter (but not both)
FD=OI+B
B=FD-OI
Using V and VI
B= M - (1/4)*x
Using IV
B = (2/5)*x - (1/4)*x
B= (3/20)*x
3X/20 (option a) of the pastries submitted by Rashid and Mikhail were brushed with butter
Answer:
dont know what grade your in but looks like u need to help me
Step-by-step explanation:
Answer:
20%
Step-by-step explanation:
i divided the percentages each by 45 and so% was 4.4. 20% was the closest to 45.
Answer:
57 deg
Step-by-step explanation:
Rhombus ABCD has diagonals AC and BD which intersect at point E.
The diagonals of a rhombus divide the rhombus into 4 congruent triangles.
If you find the measures of the angles of one of the triangles, then you know the measures of the angles of all 4 triangles.
Also, the diagonals of a rhombus are perpendicular.
Look at triangle BCE.
m<BCE = 33
m<BEC = 90
m<BCE + m<BEC + m<CBE = 180
33 + 90 + m<CBE = 180
m<CBE = 57
<ABE in triangle ABE corresponds to <CBE in triangle BCE.
m<ABE = m<CBE = 57
Answer: 57 deg
