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3 years ago

35 POINTS. I need help! Please!

Mathematics

1 answer:

topjm [15]3 years ago

7 0

There is no solution for the first one

if you eliminate y you get 2 equations
-13x - 13z = -25
-13x - 13x = -15

- there is no solution to theses

a23 means the element in the second row and the 3rd column

so its -5

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Order the decimals from least to greatest 3.4897, 3.3487, 1.5467, 3.348

Anna71 [15]

Answer:

1.5467, 3.348, 3.3487, 3.4897

Step-by-step explanation:

Remember to compare each one number at a time!

For the first number, only one number is 1 while the others are 3 making it the lowest.

Then when comparing 3.348 and 3.3487, it can be implied that there is a 0 at the end of 3.348 because it makes the numbers have the same # of decimal places without changing the value of the number (3.3480). That number is less than 7.

Finally, 3.4897 has a 4 in the tenths place instead of a 3 making it the highest number.

Hope this helps!

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3 years ago

you have 5 red crayons, 3 yellow crayons, 4 blue crayons and purple crayons. what multiplication would you do to find the probab

almond37 [142]

Answer:

3/46

Step-by-step explanation:

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3 years ago

Paul sketched a right angel with legs of length a, b, and h. Then he writes an expression for the length of the hypotensure. Wha

MA_775_DIABLO [31]

Answer:

Paul might have written the expression $h^2=a^2+b^2$ .

Step-by-step explanation:

Given:

Length of the leg 1 = a

Length of the leg 2 = b

Hypotenuse = h

We need the expression Paul has written:

Solution:

Now we know that;

The figure sketched by Paul is a right angle triangle.

Now by Pythagoras Theorem which states that;

"The square of the length of the hypotenuse is equal to sum of the square of the length of the legs."

equation can be framed as;

$h^2=a^2+b^2$

Hence Paul might have written the expression $h^2=a^2+b^2$ .

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3 years ago

Part A Prove that when x > 1, a triangle with side lengths a = x2 − 1, b = 2x, and c = x2 + 1 is a right triangle. Use the Py

Nataly [62]

Step-by-step explanation:

Given : A triangle with side lengths $a = x^2-1, b = 2x, \text{ and } c = x^2 + 1$

To find : Prove that when x > 1, it is a right triangle. Use the Pythagorean theorem and the given side lengths to create an equation. Use the equation to show that this triangle follows the rule describing right triangles. Explain your steps ?

Solution :

For right triangle the Pythagorean theorem is to be satisfied.

i.e. $c^2=a^2+b^2$