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jekas [21]
3 years ago
12

35 POINTS. I need help! Please!

Mathematics
1 answer:
topjm [15]3 years ago
7 0
There is no solution  for the first one

if you eliminate y   you get 2 equations
-13x - 13z = -25
-13x - 13x = -15    

- there is no solution to theses

a23  means the element in the second  row and the 3rd column

so its -5 
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SIZIF [17.4K]
The answer is C hope this helps
4 0
3 years ago
Read 2 more answers
Find the linear function with the following properties. <br><br> f(0)=−9 Slope of f=−8
Ratling [72]

Answer:

  • f(x) = -8x - 9

Step-by-step explanation:

<h3>Given </h3>

<u>Function f, with </u>

  • f(0) = -9
  • Slope of f = -8
<h3>To find</h3>
  • Linear function
<h3>Solution</h3>

<u>Slope-intercept formula</u>

  • f(x) = mx + b
  • f(0) = -9 means y-intercept b = -9, and the slope is m = - 8

<u>So the function is</u>

  • f(x) = -8x - 9
6 0
3 years ago
(cot^2x - 1)/(csc^2x) = cos2x​
Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

cos(2x)=cos^2x-sin^2x,

cos(2x)=1-2sin^2x, and

cos(2x)=2cos^2x-1

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants.  Rewriting gives you:

\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}

And canceling out the sin^2 x leaves us with just

cos^2x-sin^2x which is one of our identities.

5 0
3 years ago
I need to know plz help
zzz [600]

Answer:

122in^2

Step-by-step explanation:

A= 10x10x3.14 = 314in^2

Ar= 12x16= 192in^2

Asr= 314-192= 122in^2

8 0
3 years ago
Use the change of variables s=x+3y, t=y to find the area of the ellipse x2+6xy+10y2≤1.
MArishka [77]

t=y\implies s=x+3t\implies x=s-3t

Then

x^2+6xy+10y^2=(s-3t)^2+6(s-3t)t+10t^2=s^2+t^2\le1

which is a disk of radius 1, hence with area \pi.

5 0
3 years ago
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