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Rashid [163]
3 years ago
8

This is homework. please help with the answer for both 11a and 11b :))

Mathematics
1 answer:
RideAnS [48]3 years ago
3 0
11a:
3x+5=5x-57
3x-5x=-57-5
-2x=-62
x=31
11b:
2x+2x+4x+150+4x+150=360
12x+300=360
12x=360-300
12x=60
x=5

hope this helped !!
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Which of the following describes the graph of y = x² - 225?
lara [203]

Answer:

option 4. The graph has zeroes at x = 15 an x = -15 and it opens upward.

Step-by-step explanation:

we have

y=x^{2} -225

This is the equation of a vertical parabola open upward (the leading coefficient is positive)

The vertex represent a minimum

The vertex is the point (0,-225)

The axis of symmetry is x=0 (y-axis)

Find the x-intercepts (values of x when the value of y is equal to zero)

For y=0

0=x^{2} -225\\x^2=225

square root both sides

x=\pm15

therefore

The graph has zeroes at x = 15 an x = -15 and it opens upward.

3 0
3 years ago
What is obtained by squaring the standard deviation?
anastassius [24]
<h2>Answer:</h2>

Variance

<h2>Step-by-step explanation:</h2>

The standard deviation is related to the variance. The standard deviation measures the variation or dispersion of a set of data and is represented by the Greek letter sigma \sigma, while the variance measures how far a set of  numbers are spread out from their average value. The variance is obtained by squaring the standard deviation, so the variance can be found as \sigma^{2}

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3 years ago
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lyudmila [28]

Answer:

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Step-by-step explanation:

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3 years ago
What is the slope of the line that is perpendicular to the line that passes through (-2, 7) and (4, 9)? Type a numerical answer
kodGreya [7K]

Answer:

Therefore m_{2} = -3.

Step-by-step explanation:

i) let us say the slope of the line passing through (-2,7) and (4,9) is m_{1}.

ii) to find the slope of the line passing through two points (x_{1}, y_{1}) and (x_{2},y_{2}) we use the formula m = \dfrac{y_{2} - y_{1} }{x_{2}  - x_{1} }. Therefore we can say that  m_{1} = \dfrac{9 - 7}{4 - (-2)} = \dfrac{1}{3}.

iii) let us say the slope of the perpendicular line to the line  passing through (-2,7) and (4,9) is m_{2}

iv) from the formula for the slopes of a line and the line perpendicular to it which is given by m_{1} × m_{2} = -1, therefore m_{2} = -1 ÷  m_{1} = -3. Therefore m_{2} = -3

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3 years ago
Simplify 2y+(4+5y) expression
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