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Anettt [7]
3 years ago
5

Muscles cells are called?

Chemistry
2 answers:
Marizza181 [45]3 years ago
8 0

muscles cells are called Myocyte .

evablogger [386]3 years ago
6 0

Answer:

They are called Myocyte.

Explanation:

A myocyte is said to be the type of cells that is found in muscle tissue. They are structurally long and also posses tubular cells that inhibits develop from myoblasts to form myogenesis process which are muscles.

Within a skeletal muscle fibre, there are many myocytes. arranged parallel to one another which gives the fibre a striated appearance. They are contractile parts of the muscle fibre.

Also, different forms of these myocytes has different qualities in our body muscles found in the cardiac, skeletal, and smooth muscle cells.

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My made-up polyatomic ion goldate acts a lot like chlorate (it has the same charge and the same number of oxygens). What would t
Keith_Richards [23]

Answer:

d. Pergoldic acid

Explanation:

chlorate = ClO₃⁻

Goldate GoO₃⁻

On this basis we can infer that HClO₄ and HGoO₄ will be similar .

HClO₄ is called perchloric acid , hence HGoO₄ will be called pergoldic acid.

8 0
3 years ago
Explain why copper is used for the<br> roofs of some buildings and magnesium is not.
Scrat [10]

Answer:

Because of the less reactivity of copper.

Explanation:

As well as being resistant to the elements and thereby less likely to be affected by rainfall, hail, and mildew than other types of roofing, copper is also one of the most fireproof materials available. Copper is also highly resistant to thermal changes and thereby doesn't deteriorate quickly.

Magnesium would also corrode PDQ. Magnesium sheeting would also pose an unacceptably high fire hazard.

3 0
2 years ago
Is air homogeneous or heterogeneous?
ivolga24 [154]

Answer:  yes, Air is a homogeneous mixture of the gaseous substances nitrogen, oxygen, and smaller amounts of other substances. Salt, sugar, and substances dissolve in water to form homogeneous mixtures. A homogeneous mixture in which there is both a solute and solvent present is also a solution

Explanation:

8 0
2 years ago
Read 2 more answers
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (<em>M)</em> is calculated from the following equation:

<em>M</em> = <em>n</em> ÷ <em>V</em>

where <em>n</em> is the number of moles of the solute in the solution, and <em>V</em> is the volume of the solution.

Accordingly, the number of moles of the solute is given by

<em>n</em> = <em>M</em> x <em>V</em>

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

<em>n </em>(1) = <em>M </em>(1) x <em>V </em>(1)

<em>n </em>(2) = <em>M </em>(2) x <em>V </em>(2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

<em>n</em> (1) = <em>n</em> (2)

and

<em>M</em> (1) x <em>V</em> (1)<em> </em>= <em>M</em> (2) x <em>V</em> (2)

For the stock solution, <em>M</em> (1) = 1.244 M, and <em>V</em> (1) is the volume needed. For the dilute solution, <em>M</em> (2) = 0,1281 M, and <em>V</em> (2) = 250.0 mL.

The volume of the stock solution needed, <em>V</em> (1), is calculated as follows:

<em>V</em> (1) = <em>M</em> (2) x <em>V</em> (2) ÷ <em>M</em> (1)

<em>V</em> (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

<em>V </em>(1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0
3 years ago
How many atoms of gold are in a pure gold coin weighing 12.0g?
grigory [225]
12.0g x 1 mol / 63.546g = 0.188839581mol 

<span>So, for every 1 mole, we have 6.022 x 10^23 of whatever we're measuring. This gives us a conversion factor of (1 mole / 6.022 x 10^23 atoms) or (6.022 x 10^23 atoms / 1 mole).
</span>
0.188839581 mol x (6.022 x 10^23 atoms) / 1 mol = 1.137191955 x 10^23 

<span>Remember from before that we are limited to 3 significant figures. Since our calculations are complete, we can now round down to: 1.14 x 10^23 </span>

<span>That should be your answer!

Hope it helps!
xo</span>
3 0
3 years ago
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