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2 years ago

If a 12 fl. Oz. Beer has a 12% abv, how many servings of alcohol is that?.

Chemistry

1 answer:

hoa [83]2 years ago

6 0

Answer:

12x0.12=1.441.44/0.6=2.4

answer: 2.4

1 serving of alcohol equals 0.6fl ounces of pure alcohol

Explanation:

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Find the molar mass of Ca(NO3)2

spayn [35]

The molar mass of Ca(NO₃)2 is 164 g/mol

<u><em> Explanation</em></u>

Ca(NO₃)2 is made up of Ca , N and O elements

Therefore the molar mass of Ca(NO₃)2 = molar mass of Ca + molar mass of N +molar mass of O

from periodic table the molar mass of Ca is 40 g/mol

for N = 14 g/ mol

for O = 16 g/mol. since they are 3 atoms of O in Ca(NO₃)2 the molar mass = 16 x3 = 48 g/mol

The molar mass of Ca(NO₃)2 = 40 g/mo + [(14 g/mol + 48 g/mol) 2] =164g/mol

6 0

3 years ago

Read 2 more answers

T. Svedberg measured the molecular weight of carbonyl hemoglobin by velocity centrifugation. In this experiment, 0.96 g of prote

Natalija [7]

Answer:

The molecular weight is 77.7 kg/mol

Explanation:

The molecular mass of hemoglobin is equal to:

$M=\frac{RTs}{D(1-Vp)}$

Where

R = molar gas constant = 8.315 J/K mol

p = density = 0.998 g/mL

V = specific volume = 0.755 mL/g

s = sedimentation rate = ?

D = diffusion rate = 7x10⁻¹¹m²/s

T = temperature = 303 K

The sedimentation rate is equal to:

$s=\frac{1}{w^{2}t } ln(\frac{x_{b,t} }{x_{b,0} } )$

Where

w = angular velocity = 39300 rpm = 246929.18 rad/min

xb,30 = boundary midpoint distance at 30 min = 4.525 + 0.074 cm

t = time = 30 min

xb,0 = boundary midpoint distante at 0 min = 4.525 cm

$s=\frac{1}{246929.18^{2}*30 } ln(\frac{4.525+0.074}{4.525} )=8.87x10^{-13} min=5.32x10^{-13} s$

The molecular weight is:

$M=\frac{8.315*303*5.32x10^{-13} }{7x10^{-11}*(1-(0.755*0.998)) } =77.7kg/mol$

5 0

3 years ago

What’s the best answer

In-s [12.5K]

C) is correct, because there are 2 carbons and 4 oxygens on both sides, making the equation balanced.

7 0

3 years ago

Which element is rolled into a foil and used in your kitchen?

Doss [256]

Aluminum is the correct answer

8 0

3 years ago

A 9.86 g sample of an aqueous solution of hydroiodic acid contains an unknown amount of the acid. If 27.5 mL of 0.337 M potassiu

Aneli [31]

Answer:

88.3% of hydroiodic acid is found

7 0

3 years ago