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OverLord2011 [107]
3 years ago
14

How many atoms of gold are in a pure gold coin weighing 12.0g?

Chemistry
1 answer:
grigory [225]3 years ago
3 0
12.0g x 1 mol / 63.546g = 0.188839581mol 

<span>So, for every 1 mole, we have 6.022 x 10^23 of whatever we're measuring. This gives us a conversion factor of (1 mole / 6.022 x 10^23 atoms) or (6.022 x 10^23 atoms / 1 mole).
</span>
0.188839581 mol x (6.022 x 10^23 atoms) / 1 mol = 1.137191955 x 10^23 

<span>Remember from before that we are limited to 3 significant figures. Since our calculations are complete, we can now round down to: 1.14 x 10^23 </span>

<span>That should be your answer!

Hope it helps!
xo</span>
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Reaction Rates
inn [45]

Answer:

PART A 1st order in A and 0th order in B

Part B The reaction rate increases

Explanation:

<u>PART A </u>

The rate law of the arbitrary chemical reaction is given by

-r_A=k\times\left[A\right]^\alpha\times\left[B\right]^\beta\bigm

Replacing for the data

Expression 1 0.00639=k\times{0.12}^\alpha\times{0.22}^\beta

Expression 2 0.01280=k\times{0.24}^\alpha\times{0.22}^\beta

Expression 3 0.00639=k\times{0.12}^\alpha\times{0.11}^\beta

Making the quotient between the fist two expressions

\frac{0.00639}{0.01280}=\left(\frac{0.12}{0.24}\right)^\alpha

Then the expression for \alpha

\alpha=\frac{ln\frac{0.00639}{0.01280}}{ln\frac{0.12}{0.24}}=1\bigm

Doing the same between the expressions 1 and 3  

\frac{0.00639}{0.00639}=\left(\frac{0.22}{0.11}\right)^\beta

Then

\beta=\frac{ln\frac{0.00639}{0.00639}}{ln\frac{0.22}{0.11}}=0\bigm

This means that the reaction is 1st order respect to A and 0th order respect to B .

<u>PART B </u>

By the molecular kinetics theory, if an increment in the temperature occurs, the molecules will have greater kinetic energy and, consequently, will move faster. Thus, the possibility of colliding with another molecule increases. These collisions are necessary for the reaction. Therefore, an increase in temperature necessarily produces an increase in the reaction rate.

4 0
3 years ago
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sammy [17]

Answer:

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People will go crazy wife or go to h*** in a become World War 3

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The human body is 0.0040% iron. How many milligrams of iron does a 165 pound person contain?​
Fofino [41]

Answer:

in a body of 165 pounds, the iron content is 2993.707 mg

Explanation:

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⇒ mass iron / mass human = 4 E-5

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⇒ mass iron = 165 pounds * 4 E-5

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⇒ mass iron = 2993.707 mg iron

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