Question

What is the equation of a line perpendicular to y=14x−3 and passes through the point (−2, 4)?

Answer 1

Answer:

they answer would be y = 3x + 2

Step-by-step explanation:

Convert the equation to slope intercept form to get y = –1/3x + 2.  The old slope is –1/3 and the new slope is 3.  Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

With the new slope, use the slope intercept form and the point to calculate the intercept: y = mx + b or 5 = 3(1) + b, so b = 2

So y = 3x + 2