The degree of vertex b is b
<h3>
Answer: D) 31</h3>
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Explanation:
The expression g(f(2)) has f(2) as the inner function.
Let's compute f(2)
This means we plug x = 2 into the f(x) function
f(x) = 4x^3 - 10
f(x) = 4(x)^3 - 10
f(2) = 4(2)^3-10
f(2) = 4*8-10
f(2) = 32-10
f(2) = 22
Now we'll plug this into the g(x) function
This is because g(f(2)) = g(22). I've replaced f(2) with 22
So,
g(x) = (3x-4)/2
g(22) = (3*22-4)/2
g(22) = (66-4)/2
g(22) = 62/2
g(22) = 31
Therefore, g(f(2)) = 31
The answer to your question is-9
From the given information, the parabola is a sideways parabola facing left with vertex at the origin.
Required equation is (y - 0)^2 = 4p(x - 0)
y^2 = 4px
But 0 + p = -8 => p = -8
Therefore, required equation is y^2 = 4(-8)x
y^2 = -32x
Elaborate what do the symbols stand for pmme if you need more help.
