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Keith_Richards [23]
2 years ago
10

Name two pairs of congruent angles in each figure​

Mathematics
2 answers:
AnnZ [28]2 years ago
8 0
Use your protractor and find out
Anna007 [38]2 years ago
6 0
EF and GH. those are the right answers
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An integer N is to be selected at random from {1, 2, ... , (10)3 } in the sense that each integer has the same probability of be
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Probability of N Divisible by 3 - 0.33

Probability of N Divisible by 5 - 0.2

Probability of N Divisible by 7 - 0.413

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Step-by-step explanation:

Given data:

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Thus total number of ways by which 1000 is divisible by 3 i.e. 1000/3 = 333.3

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total number of ways by which 1000 is divisible by 5 i.e. 1000/5 = 200

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total number of ways by which 1000 is divisible by 7 i.e. 1000/7 = 142.857

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total number of ways by which 1000 is divisible by 15 i.e. 1000/15 = 66.667

Probability of N divisible by 15 {N%15 = 0 } = \frac{66.667}{1000} = 0.066

total number of ways by which 1000 is divisible by 105 i.e. 1000/105 = 9.52

Probability of N divisible by 105 {N%105 = 0 } = \frac{9.52}{1000} = 0.0095

similarly for N is selected from 1,2.....(10)^k where K is  large then the N value. Therefore effect of k will remain same as previous part.

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0.17 is larger as .035 is in the hundredth spot and is lower in value than the tenth spot, in which 0.17 is at. <span />
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