3 years ago

Giving away 14pts. This is Geometry and I need help on how to find the value of A.

Mathematics

1 answer:

Firdavs [7]3 years ago

8 0

I think it is 96 but I could be wrong

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3 years ago

Help please i don’t know how to do it

Norma-Jean [14]

Answer:

Step-by-step explanation:

$\frac{dy}{dx}=x^{2}(y-1)\\\frac{1}{y-1} \text{ } dy=x^{2} \text{ } dx\\\int \frac{1}{y-1} \text{ } dy=\int x^{2} \text{ } dx\\\ln|y-1|=\frac{x^{3}}{3}+C\\$

From the initial condition,

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So we have that $\ln |y-1|=\frac{x^{3}}{3}+\ln 2\\e^{\frac{x^{3}}{3}+\ln 2}=y-1\\2e^{\frac{x^{3}}{3}}=y-1\\y=2e^{\frac{x^{3}}{3}}+1$

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Likurg_2 [28]

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3 years ago

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svetlana [45]

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

That's what would REALLY happen, or did you want me to answer the math problem?

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