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2 years ago

8

t ‘ 1 a ‘ 2 4 3 ‘ ‘ ‘ mm _ ‘ ‘ ‘ ‘ ‘ m 1 ‘ } Wu W guys ‘ I m NJ : IN M H ‘ l w i ‘ \ m ‘ , ' WM '11 WNW NM NM W ‘ “ Wm MPH 1 MM

” ‘ ‘ ‘ ‘ ‘ H M “ M ‘ ‘ 1y WW ‘ help

1 answer:

valentinak56 [21]2 years ago

8 0

Angle 1 and angle 5 are equal so you can set the equations equal to each other. 60 - 2x = 70 - 4x
60 + 2x = 70
2x = 10
x= 5

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you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

2 years ago

OlgaM077 [116]

Answer:

Point on Midline (0,3)

Maximum (9π/2,3)

Minimum (-9π/2,-3)

Step-by-step explanation:

in the given sine function which is in the form of f(x) = a sin(bx+c) +d

a = amplitude

period = frequency = 18π

Therefore b = 2π/18π = 1/9

Y intercept = vertical shift = 3

Horizontal shift = d = 0

Therefore the sine function will be

f(x) = 6 sin(x/9) + 3

Now first point on the midline is (0,3)

Second point is maximum (9π/2,9)

Third point be a minimum value ( -9π/2,-3)

7 0

2 years ago

Find the values of x and y leave answers in simplest radical form. *The altitude is:

jok3333 [9.3K]

$x = \sqrt{ { \sqrt{18} }^{2} + {2}^{2} } = \sqrt{18 + 4} = \sqrt{22} \\ y = \sqrt{ { \sqrt{18} }^{2} + {9}^{2} } = \sqrt{18 + 81} = \sqrt{99} = 3\sqrt{11}$

5 0

3 years ago

How many time can 25 go in 389

iren2701 [21]

15 times is the answer

5 0

2 years ago

Read 2 more answers

You are painting the root of a boathouse. You are going to place the base of a ladder 12 feet from the boathouse. How long does

jolli1 [7]

Answer:

37 ft

Step-by-step explanation:

The ladder forms a right triangle as it elan's against the wall of the boat house.

Thus, the length of the ladder can be determined using Pythagorean theorem.

c² = a² + b²

c = length of ladder

a = 35 ft

b = 12 ft

Plug in the values

c² = 35² + 12²

c² = 1,225 + 144

c² = 1,369

c = √1,369

c = 37

Therefore, to reach the roof of the boathouse, the length of the ladder = 37 ft

4 0

2 years ago