Answer:
Width = 2
Length = 5
Step-by-step explanation:
let A be the area of the rectangle
L be the length of the rectangle
w be the width of the rectangle
<u><em>Formula</em></u>: ‘<u><em>area of a rectangle</em></u>’
A = L × w
…………………………………………………
A = L × w
⇔ 10 = (w + 3) × w
⇔ 10 = w² + 3w
⇔ w² + 3w - 10 = 0
<u><em>Solving the quadratic equation</em></u> w² + 3w - 10 = 0 :
Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49
then √Δ = 7


-5 is not valid ,because w represents the width
which must be a positive number
Then w = 2
<u><em>Conclusion</em></u>:
Width = 2
Length = 2 + 3 = 5
3x+2y=5.44
it's a two variable problem which can't be solved algebraically unless you are given the weight of one of the balls.
Answer:
its cut off Step-by-step explanation:
its cut off dude
There is an 80% chance to find a red or purple. The total number of markers is 40 and the combined number of red and purple is 32. Dividing 32 by 40 gives you 4/5, 0.8, or 80%
Answer:
1) x ≤ 8
2) s < 11
3) c ≤ 4.8
Step-by-step explanation:
1) x+9-3≤14
x+6≤14
x ≤ 8
2) 44>7+s+26
44>33+s
s < 44-33
s <11
3) 6.1 - 0.3 ≥ c + 1
5.8 ≥ c + 1
c ≤ 4.8