Answer:
see explanation
Step-by-step explanation:
If 2 lines are perpendicular then the product of their slopes equals - 1
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Consider the given equations
3x - 4y = 12 ( subtract 3x from both sides )
- 4y = - 3x + 12 ( divide terms by - 4 )
y = 
x - 3 ← in slope- intercept form
with slope m =
3y = 12 - 4x = - 4x + 12 ( divide terms by 3 )
y = - 
x + 4 ← in slope- intercept form
with slope m = -
Then
× - = - 1
Since the product of their slopes = - 1 then the lines are perpendicular
Answer:
the water is 2.2 meters deep
Step-by-step explanation:
Answer:
Part A
The bearing of the point 'R' from 'S' is 225°
Part B
The bearing from R to Q is approximately 293.2°
Step-by-step explanation:
The location of the point 'Q' = 35 km due East of P
The location of the point 'S' = 15 km due West of P
The location of the 'R' = 15 km due south of 'P'
Part A
To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that 
= 
, the right triangle ΔRPS is an isosceles right triangle
∴ ∠PRS = ∠PSR = 45°
The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°
Part B
∠PRQ = arctan(35/15) ≈ 66.8°
Therefore the bearing from R to Q = 270 + 90 - 66.8 ≈ 293.2°
Answer:
0.56
Step-by-step explanation:
sin x
tan x is defined as -------------
cos x
and we can solve this for sin x: sin x = (cos x)(tan x)
which here is: sin x = 0.83(0.67) = 0.56 (rounded up from 0.5561)
The answer is -4.
i hope it helps you!
