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agasfer [191]
1 year ago
8

Divide using long division. State the​ quotient, q(x), and the​ remainder, r(x).

Mathematics
1 answer:
kolezko [41]1 year ago
7 0
What are u supposed to be dividing
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Miguel collected aluminum cans for recycling. He collected a total of 150 cans. If 58% of the cans he collected were soda cans h
Romashka-Z-Leto [24]

Given:

• Total number of cans collected = 150

,

• Percent of cans that were soda = 58%

Let's find the number of other cans he collected.

To find the number of other cans, since the percent of soda is 58%, let's find the pecent of other cans.

Percent of other cans = 100% - 58% = 42%

The percent of other cans collected was 42%.

Now, to find the number of other cans collected, let's find 42% of the total number of cans collected 150.

We have:

42\text{ \% }\ast150\Longrightarrow0.42\times150=63

Therefore, the number of other cans collected is 63 cans.

ANSWER:

63 cans

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11 months ago
What are the coordinates of point A?
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3 years ago
Line N passes through the points (–1, 4) and (–1, –4).Which is true of line N? Line N is a vertical line with an undefined slope
Marrrta [24]

Answer:

Line N is a vertical line with an undefined slope.

Step-by-step explanation:

When the points that line N passes through are graphed, they form a vertical line.

All vertical lines have an undefined slope.

We can also check if it's undefined by finding the slope.

m=\frac{-4-4}{-1+1}=\frac{-8}{0}

The quotient would be undefined. You cannot divide by zero.

Hope this helps.

7 0
3 years ago
How do you write 0.3 as a fraction?
dimaraw [331]

Answer:

3/10

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7 0
3 years ago
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This shape is made using three semicircles The smaller semicircle have diameters of 10cm Calculate the shaded area Take 3.142 an
CaHeK987 [17]

Answer:

The shaded area is 314.2 cm²

Step-by-step explanation:

Here we have the diameter, d₁ of the smaller semicircles as 10 cm

We note that the larger semicircle is subtended (bounded) by the two smaller semicircles;

1 shaded small semicircle and the other is blank

Therefore, the diameter, d₂ of the large semicircle = 10 + 10 = 20 cm

Also the area of the shaded figure consists of the removal of one small semicircle and the addition of the other semicircle to the area of the larger semicircle such that the area of the shaded figure is as follows

Shaded area of figure = π·d₂²/4 + π·d₁²/4 - π·d₁²/4 = π·d₂²/4 = π×20²/4 = 100×3.142 = 314.2 cm²

Shaded area = 314.2 cm².

6 0
3 years ago
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