All categories

3 years ago

A right triangle has a height of 12 and a width of 5. How long is the diagonal?

Mathematics

2 answers:

Dafna1 [17]3 years ago

7 0

Using Pythagoras:

12^2+5^2= 144+25=169

√169= 13

Artemon [7]3 years ago

5 0

The answer would be 13

You might be interested in

What value of Y will satisfy the given equation y divided by 2y — 15 = 7/5

guapka [62]

Answer:

$\huge\boxed{\sf y = \frac{41}{5} \ OR \ y = 8\frac{1}{5} }$

Step-by-step explanation:

$\sf 2y-15 = \frac{7}{5} \\\\Adding \ 15 \ to \ both \ sides\\\\2y = \frac{7}{5} + 15\\\\2y = \frac{7+75}{5} \\\\2y = \frac{82}{5} \\\\Dividing \ both \ sides \ bu 2\\\\y = \frac{82}{5*2} \\\\y = \frac{41}{5}$

Hope this helped!

<h2>~AnonymousHelper1807</h2>

3 0

3 years ago

What are the coordinates of the image of the point (2, –6) under a dilation with a center of (0, 0) and a scale factor of 1/2

ycow [4]

That would be (1, -3) because you basically divide the coordinates by the scale factor, in this case 2.

8 0

3 years ago

Please help me. Thank you!!

Sliva [168]

Answer:

B. 55°

Step-by-step explanation:

7 0

3 years ago

2x+6y=-24 converted into a slope intercept?

Svetllana [295]

Answer:

y=1/3x+4

Step-by-step explanation:

6 0

3 years ago

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

3 years ago