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3 years ago

5

What will be the total watt demand for the living area of this Dwelling?

1 answer:

natka813 [3]3 years ago

5 0

Https://www.ecmweb.com/national-electrical-code/code-basics/article/20886603/dwelling-unit-calculations

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If g(x) = -2x5 - 4, find g(2).

miskamm [114]

$g(x)+-2x^5-4$

Substitute the value of x = 2 to the equation:

$g(2)=-2\cdot2^5-4=-2\cdot32-4=-64-4=-68$

7 0

3 years ago

Which statement is true about the product of 0.031 and 0.31?

Sladkaya [172]

Answer:

I believe the answer is c

Sorry if it is wrong still looking for answer

8 0

3 years ago

Read 2 more answers

Please explain i will mark brainliesttt!

Sati [7]

Answer:

<em>Answer is </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

$given \: the \: line \: n \: passes \: through \\ \: ( - 3, - 7.5) \: \: and(2, - 5) \\ the \: equation \: of \: the \: line \: is \\ \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ here \: x1 = - 3 \: \: \: y1 = - 7.5 \\ and \: \: x2 = 2 \: \: \: y2 = - 5 \\ \frac{y - ( - 7.5)}{ - 5 - ( - 7.5)} = \frac{x - ( - 3)}{2 - ( - 3)} \\ \frac{y + 7.5}{ - 5 + 7.5} = \frac{x + 3}{2 + 3} \\ \frac{y + 7.5}{2.5} = \frac{x + 3}{5} \\ dividing \: by \: 5 \: on \: both \: side s\\ \frac{y + 7.5}{0.5} = \frac{x + 3}{1} \\ 0.5(x + 3) = y + 7.5 \\ 0.5x + 1.5 = y + 7.5 \\ 0.5x - y - 6 = 0 \\ is \: the \: required \: equation.$

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

5 0

3 years ago

X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square

swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = $-\frac{4}{5}x+\frac{58}{5}$

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

[x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

(x + 2)² + (y - 5)²- 29 + 20 = 30

(x + 2)² + (y - 5)²- 9 = 30

(x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

Slope of the line joining this point to the center (-2, 5),

$m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

= $\frac{10-5}{2+2}$

= $\frac{5}{4}$

Let the slope of the tangent which is perpendicular to this line is ' $m_{2}$ '

Then by the property of perpendicular lines,

$m_{1}\times m_{2}=-1$

$\frac{5}{4}\times m_{2}=-1$

$m_{2}=-\frac{4}{5}$

Now the equation of the line passing though (2, 10) having slope $m_{2}=-\frac{4}{5}$

y - y' = $m_{2}(x-x')$

y - 10 = $-\frac{4}{5}(x-2)$

y - 10 = $-\frac{4}{5}x+\frac{8}{5}$

y = $-\frac{4}{5}x+\frac{8}{5}+10$

y = $-\frac{4}{5}x+\frac{58}{5}$

Therefore, equation of the line will be, y = $-\frac{4}{5}x+\frac{58}{5}$

7 0

3 years ago

If you don’t help me your a criminal

STALIN [3.7K]

Answer:

take angle U as reference angle

using sine rule

sin U=opposite/hypotenuse

sinU=42/42

sin U=1

sin 90=1

therefore the value of U is 90 degree

Step-by-step explanation:

6 0

3 years ago