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3 years ago

Use fraction strips to write 2 4/5 as an equivalent improper fraction.

Mathematics

1 answer:

Anon25 [30]3 years ago

7 0

Answer:

14/5

Step-by-step explanation:

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LMN≅PQR

tresset_1 [31]

<span>LMN≅PQR means that point L is equal to P, point M is equal to Q, and point N is equal to R. All lines are the same.

Point Q has an angle of 72, which means that point M also has an angle of 72.

Now you have two angles to find x. All interior angles of a triangle add up to 180, so you can set up the following equation to find x:

72 + 36 + x = 180

Subtract 36 from both sides.

72 + x = 144

Subtract 72 from both sides.

x = 72

The angle of point L, x, is 72.

</span>

7 0

4 years ago

Read 2 more answers

Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).

balandron [24]

If it is bisector then it co ordinate points is in mid way(3,-2)

and it is perpendicular so its slope m2=-1/m1
where m1 is slope of another line passes through (4,1) nd (2,-5)

m1=-5-1/2-4=3
m2==-1/3

so equation of line is
y-3= -1/3(x+2)

4 0

3 years ago

Read 2 more answers

What is Four times the number +8 in Algebraic expression for

mario62 [17]

I think the answer is 32x

3 0

3 years ago

I need help ASAP will mark you the brainliest

Vadim26 [7]

Answer:

Step-by-step explanation:

<DCE = BCA (vertical angles are congruent)

DC corresponds to CB,

DC/CB = 15/5 = 3

EC corresponds to CA,

EC/CA = 12/4 = 3

Thus, two sides in ∆ABC are proportional to two corresponding sides in ∆EDC, and also, the included angle in ∆ABC and ∆EDC are congruent to each other. Therefore, based on the SAS Similarity Theorem, ∆ABC and ∆EDC are similar.

4 0

3 years ago

April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how

Ostrovityanka [42]

40 adult tickets were sold and 35 children tickets were sold

<em><u>Solution:</u></em>

Let "a" be the number of adult tickets sold

Let "c" be the number of children tickets sold

Cost of 1 adult ticket = $ 8

Cost of 1 children ticket = $ 5

<em><u>Given that April sold 75 tickets to the school Christmas play and collected $495</u></em>

Number of tickets sold = 75

number of adult tickets sold + number of children tickets sold = 75

a + c = 75 ----- eqn 1

<em><u>Given that April collected $495</u></em>

Thus we can frame a equation as:

number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495

$a \times 8 + c \times 5 = 495$

8a + 5c = 495 ----- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

From eqn 1,

a = 75 - c ---- eqn 3

Substitute eqn 3 in eqn 2

8(75 - c) + 5c = 495

600 - 8c + 5c = 495

-3c = 495 - 600

-3c = - 105

Substitute c = 35 in eqn 3

a = 75 - 35

Thus 40 adult tickets were sold and 35 children tickets were sold

8 0

3 years ago