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3 years ago

Which of the following statements is true?

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

3 0

I’m pretty sure the answer is b :)

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The following table shows the speeds at which Jeff does 4 activities. For example, biking has a rate of 19 miles in 2 hours. Whi

ExtremeBDS [4]

The type of activity that Jeff does at a speed of 4.5 miles per hour is Swimming

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<em>This problem is about Kinematics.</em>

We will solve it in the following way

$\texttt{Speed of Biking} = \texttt{Distance of Biking} \div \texttt{Time Taken}$

$\texttt{Speed of Biking} = \texttt{19} \div \texttt{2}$

$\texttt{Speed of Biking} = 9.5 \texttt{ miles per hour}$

$\texttt{ }$

$\texttt{Speed of Walking} = \texttt{Distance of Walking} \div \texttt{Time Taken}$

$\texttt{Speed of Walking} = \texttt{14} \div \texttt{4}$

$\texttt{Speed of Walking} = 3.5 \texttt{ miles per hour}$

$\texttt{ }$

$\texttt{Speed of Running} = \texttt{Distance of Running} \div \texttt{Time Taken}$

$\texttt{Speed of Running} = \texttt{15} \div \texttt{3}$

$\texttt{Speed of Running} = 5 \texttt{ miles per hour}$

$\texttt{ }$

$\texttt{Speed of Swimming} = \texttt{Distance of Swimming} \div \texttt{Time Taken}$

$\texttt{Speed of Swimming} = \texttt{18} \div \texttt{4}$

$\texttt{Speed of Swimming} = \boxed{4.5 \texttt{ miles per hour}}$

$\texttt{ }$

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437
Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

3 0

3 years ago

Read 2 more answers

Use the compound interest formula to find the present value P, for the following given values.

Nookie1986 [14]

The question is not valid

3 0

3 years ago

Create an equivalent ratio to 10:16 by dividing both sides by 2. What is the equivalent ratio?

Darya [45]

10 / 2 = 5

16 / 2 = 8

The equivalent ratio is 5:8

5 0

2 years ago

A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w

AfilCa [17]

Answer:

$\frac{15}{4802}$ , $\frac{15}{9604}$ , $\frac{9}{2401}$ , $\frac{9}{4802}$

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: $\frac{4}{14}$

green: $\frac{2}{14}$

yellow: $\frac{3}{14}$

blue: $\frac{5}{14}$

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = $\frac{3}{14} \cdot \frac{4}{14} \cdot \frac{2}{14} \cdot \frac{5}{14} =\frac{15}{4802}$

Removing 1 blue, 1 green, 1 green, and 1 yellow = $\frac{5}{14} \cdot \frac{2}{14} \cdot \frac{2}{14} \cdot \frac{3}{14} =\frac{15}{9604}$

Removing 1 red, 1 red, 1 yellow, and 1 yellow = $\frac{4}{14} \cdot \frac{4}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} =\frac{9}{2401}$

Removing 1 green, 1 yellow, 1 yellow, and 1 red = $\frac{2}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} \cdot \frac{4}{14} =\frac{9}{4802}$

4 0

2 years ago

A baby’s t-shirt requires 2/9 yards of fabric. How many t-shirts can be made from 38 yards?

Bess [88]

8 4/9 hope this helps!!!

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3 years ago