Answer: 11.63%
Step-by-step explanation:
Given : The average time taken for your Internet service provider to remotely resolve a trouble ticket has a Normal distribution with a mean of 4.3 hours and a standard deviation of 4.3 hours.
i.e.
and 
Let x denotes the time taken for your Internet service provider to remotely resolve a trouble ticket ( in hours).
The probability time can you expect to wait longer than a full (8-hour) business day for a resolution :
![P(x>8)=1-P(\leq8)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{8-4.3}{3.1})\\\\=1-P(z\leq1.1935)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\ =1-0.8837\ \ [\text{By z-table}]\\\\=0.1163=11.63\%](https://tex.z-dn.net/?f=P%28x%3E8%29%3D1-P%28%5Cleq8%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B8-4.3%7D%7B3.1%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1.1935%29%5C%20%5C%20%5B%5Cbecause%5C%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%20%3D1-0.8837%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.1163%3D11.63%5C%25)
Therefore , the percent of the time can you expect to wait longer than a full (8-hour) business day for a resolution = 11.63%
N - 2 / - 3 = - 6 (1) multiply both sides by -3 to get n - 2 alone
n - 2 = 18 (2) add 2 to both sides; 2 on left side gets cancelled so we can now have n all alone
n = 20
Answer:
0.3
Step-by-step explanation:
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