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NISA [10]
3 years ago
15

At 7p.m last night the temperature was 10 °f at 7

Mathematics
1 answer:
adoni [48]3 years ago
8 0
10+2=12
The answer is 12
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13 Solve the inequality n+7&lt;5n-8<br>​
Papessa [141]

Answer:

3.75 < n

Step-by-step explanation:

n + 7 < 5n - 8

Add 8 to both sides

n + 7 + 8 < 5n

n  + 15 < 5n

Subtract 'n' from both sides

15 < 5n - n

15 < 4n

Divide both sides by 4

\frac{15}{4} < n

3.75 < n

3 0
3 years ago
Help! How would I solve this trig identity?
NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}

Then the identity can be rewritten as:

sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\

Now we can multiply both sides by cos⁴(x) to get:

\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)

Now we can use the identity:

sin²(x) + cos²(x) = 1

1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

#SPJ1

7 0
1 year ago
Which equation can be used to solve for the measure of
lapo4ka [179]

tanx = 36

Step-by-step explanation:

tabsnmshsggshsjsjsksmsndndndjf

6 0
2 years ago
In ∆ KLM above, NO // ML and &lt; KNO = &lt; KON. Find m &lt; MNL =
4vir4ik [10]

Answer: In ∆ KLM above, NO // ML and < KNO = < KON. Find m < MNL =

Step-by-step explanation: dUNNO

6 0
2 years ago
On the way to school, a student rides his bike to the bus stop. He then waits a few minutes for the bus to come and rides the bu
andriy [413]

Answer:

No, the graph is only increasing while the student rides his bike, rides the bus, and walks. It is stays the same while he waits for the bus and when the bus stops to let him off.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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