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LUCKY_DIMON [66]
3 years ago
14

What is true of a solution with a pH of 12

Chemistry
1 answer:
mars1129 [50]3 years ago
6 0
It is alkaline ........I need 20 characters......
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Which of the following ions would be expected to
vladimir2022 [97]

Answer:

F

Explanation:

because F had the bigger affinity than cl

3 0
3 years ago
Calculate ΔH⁰298 (in kJ) for the process P(s) + 5/2 Cl2(g) → PCl5(g) from the following information.
Viefleur [7K]

Answer:

\Delta H_{298}^{0} for the process is -375 kJ

Explanation:

  • Given reaction is a combination of the two given elementary steps.
  • Summation of change in standard enthalpy (\Delta H_{298}^{0})of the two elementary reactions give \Delta H_{298}^{0} of the reaction P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g).

P(s)+\frac{3}{2}Cl_{2}(g)\rightarrow PCl_{3}(g)......\Delta H_{1}=-287kJ

PCl_{3}(g)+Cl_{2}(g)\rightarrow PCl_{5}(g)......\Delta H_{2}=-88kJ

-----------------------------------------------------------------------------------------------------

P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g)

\Delta H_{298}^{0} = \Delta H_{1}+\Delta H_{2}=-287kJ-88kJ=-375kJ

3 0
4 years ago
Be sure to answer all parts. The balanced equation for the reaction of aluminum metal and chlorine gas is 2Al(s) + 3Cl2(g) → 2Al
Arada [10]

Answer: a) Cl_2 is the limiting reagent

b)  0.27 g of AlCl_3 will be produced.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al=\frac{0.80g}{27g/mol}=0.030moles

\text{Moles of} Cl_2=\frac{0.23g}{71g/mol}=0.003moles

2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)

According to stoichiometry :

3 moles of Cl_2 require = 2 moles of Al

Thus 0.003 moles of Cl_2 will require=\frac{2}{3}\times 0.003=0.002moles  of Al

Thus Cl_2 is the limiting reagent as it limits the formation of product and Al is the excess reagent.

b) As 3 moles of Cl_2 give = 2 moles of AlCl_3

Thus 0.003 moles of Cl_2 give =\frac{2}{3}\times 0.003=0.002moles  of AlCl_3

Mass of AlCl_3=moles\times {\text {Molar mass}}=0.002moles\times 133g/mol=0.27g

Thus 0.27 g of AlCl_3 will be produced.

8 0
4 years ago
What volume of water is needed for 0.196 mol of CdCl2 to prepare a 3.91 M solution? L
Brilliant_brown [7]

0.050 litres of the water will be required to make a 3.91 M solution with 0.196 moles in it.

Explanation:

Data given:

moles of CdCl_{2} = 0.196 Moles

Molarity of the solution = 3.91 M

Volume in litres =?

molarity is calculated by the formula:

molarity = \frac{number of moles}{volume in litres}

putting the values in the above formula and rearranging it for volume:

volume = \frac{number of moles}{molarity}

volume = \frac{0.196}{3.91}

volume = 0.050 litres

0.050 litres of the water will be required to make a 3.91 M solution with 0.196 moles in it.

Molarity is the number of moles present in a given volume of solution which is given in litres. It is the measurement of the concentration of particular solute in a solution.

4 0
3 years ago
Using alcohols as solvents offers the advantage of using ro- ions which are somewhat stronger ______ than the hydroxide ion.
podryga [215]
The answer is "Ro-ions which are somewhat stronger bases than the hydroxide ion.
These ro-ions are also known as alkoxide ions, and these are stronger bases. the reason behind this is that the alcohols are weaker acids than the water. Alcohols are also used as solvent in some organic reactions and this offers and advantage to use ro-ions.
5 0
3 years ago
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