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Nutka1998 [239]
3 years ago
6

What volume of water is needed for 0.196 mol of CdCl2 to prepare a 3.91 M solution? L

Chemistry
1 answer:
Brilliant_brown [7]3 years ago
4 0

0.050 litres of the water will be required to make a 3.91 M solution with 0.196 moles in it.

Explanation:

Data given:

moles of CdCl_{2} = 0.196 Moles

Molarity of the solution = 3.91 M

Volume in litres =?

molarity is calculated by the formula:

molarity = \frac{number of moles}{volume in litres}

putting the values in the above formula and rearranging it for volume:

volume = \frac{number of moles}{molarity}

volume = \frac{0.196}{3.91}

volume = 0.050 litres

0.050 litres of the water will be required to make a 3.91 M solution with 0.196 moles in it.

Molarity is the number of moles present in a given volume of solution which is given in litres. It is the measurement of the concentration of particular solute in a solution.

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<h3>Hess's Law</h3>

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

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You know the following reactions, with their corresponding enthalpies:

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Equation 2:  2 N₂ + 2 O₂ → 4 NO     ΔH = 361.1 kJ/mol

Equation 3: 2 H₂ + O₂→ 2 H₂O     ΔH = -483.7 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

In this case, first, to obtain the enthalpy of the desired chemical reaction you need 4 moles of NH₃ on reactant side and it is present in first equation on product side. So you need to invert the reaction, and when an equation is inverted, the sign of delta H also changes.

Now, 4 moles of NO must be a product and is present in the second equation, so let's write this as such.

Finally, you need 6 moles of H₂O on the product side, so you need to multiply by 3 the third equation to obtain the amount of water that you need. Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 3, the variation of enthalpy also.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 4 NH₃ → N₂ + 6 H₂  ΔH = 183.6 kJ/mol

Equation 2:  2 N₂ + 2 O₂ → 4 NO     ΔH = 361.1 kJ/mol

Equation 3: 6 H₂ + 3 O₂→ 6 H₂O     ΔH = -1,451.1 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O ΔH= -906.4 kJ/mol

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Learn more about Hess's law:

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