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MariettaO [177]
3 years ago
7

The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?

Mathematics
2 answers:
zavuch27 [327]3 years ago
7 0
Answer is D {4,7}

if u put those values in the equation then u will get that output {25,64}
Fudgin [204]3 years ago
5 0

Answer:

Correct option is:

{4,7}

Step-by-step explanation:

The range of the function f(k) = k² + 2k + 1 is {25, 64}.

i.e. k²+2k+1 can take only two values either 25 or 64

When k=5 ,k²+2k+1=36

when k= -5 ,k²+2k+1=16

when k=8 ,k²+2k+1=81

Hence, domain set cannot contain the points 5,8 and -5

The only option that do not contain any of these numbers is:

{4,7}

Also when k=4 , k²+2k+1=25

and when k=7 , k²+2k+1=64

Hence, Correct option is:

{4,7}

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Step-by-step explanation:

To find:

∫6x^5(x^6-2)\,dx

Solution:

Method of substitution:

Let x^6-2=t

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Put t=x^6-2

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Use (a-b)^2=a^2+b^2-2ab

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∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C

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Without using substitution:

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7 0
2 years ago
You purchase 5 pounds of apples and 2 pounds of oranges for $9.Your friend purchases 5 pounds of apples and 6 pounds of oranges
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Answer:

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Step-by-step explanation:

Let apples are represented by x

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This line in equation format can be written as:

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Subtracting eq(i) from eq(ii)

5x + 6y = 17

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8 0
3 years ago
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Step-by-step explanation:

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