y - y₁ = m(x - x₁)
y - 5 = -3(x - (-2))
y - 5 = -3(x + 2)
y - 5 = -3(x) - 3(2)
y - 5 = -3x - 6
+ 5 + 5
y = -3x - 1
(2xy+y) divided (2xy+4, if x=+6,Y-3 Help someone
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y - y₁ = m(x - x₁)
y - 5 = -3(x - (-2))
y - 5 = -3(x + 2)
y - 5 = -3(x) - 3(2)
y - 5 = -3x - 6
+ 5 + 5
y = -3x - 1