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Jet001 [13]
3 years ago
13

Please help with problem 19. (ONLY IF YOU KNOW) thanks

Mathematics
2 answers:
Stella [2.4K]3 years ago
8 0
7 cars full and 5 people on the next car
svet-max [94.6K]3 years ago
7 0
About 7 people in each
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5 to 7 and please solve with equations thx
padilas [110]

Answer:

Step-by-step explanation:

5) x + 5.4 < -1.6

x < -1.6 - 5.4

x < -7

6) x + 7.5 > -2.5

x > -2.5 - 7.5

x > -10

7) 3 ≤ 1/3 + x

x ≥ 3 - 1/3

x ≥ 5/3

4 0
3 years ago
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bixtya [17]
I think the last two are correct.
Hope it helps

8 0
3 years ago
Increase 270 by 20%​
Nana76 [90]

Answer:

first find 20 percent of 270

270 times 20 divided by 100

5400 divided by 100

54

270 plus 54

324 is your final answer

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5 0
3 years ago
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After dividing a piece of wood into four equal sections,each section is 4 in.long.How long was the piece of wood I started with
Cerrena [4.2K]

I'm going to out on a limb and say 16 in.

4 pieces * 4 in. = 16

5 0
4 years ago
Please help me! I'm spending 50 points on this question and my last two questions never even got answered!
Verdich [7]

Answer:

C.

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

\frac{3x^2 + x^4 + 2}{4x - 3}

4x - 3 makes up our denominator, the bottom part of the fraction. So

4x - 3 = 0

4x = 3

x = 3/4

So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

\frac{x^2 - 4}{x-2}

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

8 0
3 years ago
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