<h2>
<em><u>question </u></em><em><u>:</u></em><em><u> </u></em></h2>
<em><u>How many ways can three Computer Programmer positions be chosen from 45 </u></em><em><u>applicant</u></em><em><u>?</u></em>
<h2>
<em><u>answer:</u></em></h2>
<em><u>45. Okay, This is equal to 45 C three and this is equal to 45 factorial over three factorial, multiplied by 45 minus three factorial. So this implies 14190 ways.</u></em>
<h3>
<em><u>hope </u></em><em><u>this </u></em><em><u>help </u></em><em><u>you </u></em></h3>
Answer:
a = 4.8
Step-by-step explanation:
9 - 4a + 12 = 6a - 27
21 - 4a = 6a - 27
48 - 4a = 6a
48 = 10a
4.8 = a
Answer:
sorry dawg this stuff hard. lol good luck
Step-by-step explanation:
Can't read the top questions mate !
