Well, it might be something like 18x-6 = 78x2?
Have you tried that?
Answer:
a. 9.5x + 6.5(x+c) < 8 when c>0
b. Must be one child more than the no. of adults.
Step-by-step explanation:
For Cinema 1:
for adult = $9.50
for child = $6.50
For Cinema 2:
Per person regardless of age = $8.00
First of all, we will find out the condition when per person rates in both cinema are equal.
Assume x = no. of adults
y = no. of children
Rate per person in Cinema I = Rate per person in Cinema II
(9.5x + 6.5y)/(x+y) = 8
9.5x + 6.5y = 8(x+y)
9.5x + 6.5y = 8x + 8y
9.5x-8x = 8y-6.5y
=> x = y
So rates are equal when no. of adults equals no. of children
For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8
Hence we form an inequality when y = x+c and c > 0
9.5x + 6.5(x+c) < 8 when c>0
Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.
Perpendicular
Mark as brainliest
The answer would be y=60.
I think.
