the hypotenuse of the right angled triangle is 6cm more than twice the shortest side. if the third side is 2 cm less than the hy
potenuse. find the 3 sides
1 answer:
Answer:
Let the base be p
Hypotenuse = 2p +6
Perpendicular = 2p + 4
By Pythagoras theoram
(2p+6)^2 = (2p+4)^2 +p^2
=> 4p^2 +36 + 24p = 4p^2 + 16 +16p +p^2
=> 36+ 24p = p^2 + 16p + 16
=> p^2 - 8p - 20 = 0
=> p^2 - 10p +2p - 20 = 0
=> p(p-10) +2(p-10) = 0
=> (p-10)(p+2) = 0
p = 10 and - 2
Length can't be negative
So,
p = 10
Base = 10
Perpendicular = 24
Hypotenuse = 26
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