Answer:
the equation should be corrected to fit the data of the problem. With the corrected equation a mass of 0.5 grams remains after 150 years
Step-by-step explanation:
for the mass y( in grams)
y=23* (1/2)^(t/45), t ≥ 0.
the initial mass is at t=0 , then
y= 23 grams → should be 16 grams
half-life from the equation = 45 years → should be 30 years
the correct equation should be
y=16*(1/2)^(t/30), t ≥ 0
then after 150 years → t= 150
y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams
then a mass of 0.5 grams remains after 150 years
Answer:
which ones you want solved? all?
Step-by-step explanation:
The percentage of change from 45 to 56 is 24.4%
To find this, we first need to find the difference between our two values. This difference would be 11.
The next step would be to divide 11 by 45. We then move the decimal point over two spots to the right which gives us our answer.
Answer:
-12 b + 6 c + 18
Step-by-step explanation:
-4 b + 8 c + 12 - 8 b - 2 c + 6
