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sweet [91]
3 years ago
6

It costs felisa $0.20 to send a text message from her cell phone. She has already spent 5 in text messages this month if she has

a total of $12 that she can spend this month on text messages, write and solve an inequality that will give the greatest number of text messages that she can send interpret the solution
Mathematics
1 answer:
natima [27]3 years ago
8 0

Answer:

60 messages.

Step-by-step explanation:

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Find negative square root of 36. (4 points)<br> Group of answer choices
AleksAgata [21]

Answer:

-5.65685424949

Step-by-step explanation:

7 0
3 years ago
5+8=6+7 true or false​
Romashka-Z-Leto [24]

Answer: True becuase  5+8 equals 13 and 6+7 also equal 13 so that means that they are equal to each other.

Step-by-step explanation:

8 0
3 years ago
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Not sure how to solve the problem in the pic :)
yulyashka [42]

Answer:

C.

Step-by-step explanation:

do the division first then subtract 11

x/3 - 11

8 0
3 years ago
Evaluate Combination (6,6)
andrew11 [14]

Answer:

nCx = \frac{n!}{x! (n-x)!}

On this case n =6 and x =6 we got:

6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1

Step-by-step explanation:

The utility for the combination formula is in order to find the number of ways to order a set of elements

For this case we want to find the following expression:

6C6

And the general formula for combination is given by:

nCx = \frac{n!}{x! (n-x)!}

On this case n =6 and x =6 we got:

6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1

8 0
3 years ago
A trailer will be used to transport several 40-pound crates to a store. The greatest amount of weight that can be loaded into th
docker41 [41]

Given :

A trailer will be used to transport several 40-pound crates to a store.

The greatest amount of weight that can be loaded into the trailer is 1,050 pounds.

An 82-pound crate has already been loaded onto the trailer.

To Find :

The greatest number of 40-pound crates that can be loaded onto the trailer.

Solution :

Weight left = 1050 - 80 = 970 pound.

Let, number of 40 pounds crates that can be loaded are x.

x  = \dfrac{970}{40}\\\\x = 24.25

Since, crate cannot be in fraction, so maximum crate that can be loaded is 24.

Hence, this is the required solution.

7 0
3 years ago
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