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stiv31 [10]
3 years ago
9

A bag contains 144 marbles. Some are red and the rest are black.There are 11 red marbles for every black marble.How many red mar

bles are in the bag?
Mathematics
1 answer:
wolverine [178]3 years ago
3 0

Answer:

There are 132 red marbles and 12 black marbles

Work:

I made a ratio of 11:1 and multiplied both sides by 12 which gave me 132:12

132+12=144


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WHAT ARE THE THREE DIFFERENT TYPES OF ANGLES!!!!!!??
Vikentia [17]
<em>Hello there, and thank you for asking your question here on brainly.

<u>Answer: The three different types of angles are an acute angle, which is an angle that is an angle that measures from 1</u></em>° <em><u>to 89°. A right angle, that specifically measures to 90</u></em>°. <em><u>Finally, an obtuse angle that measures from 91° to 179°. An angle that also measures 180° is a straight line, and is called a straight angle. 

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6 0
3 years ago
The inside diameter of a randomly selected piston ring is a random variable with mean value 8 cm and standard deviation 0.03 cm.
S_A_V [24]

Answer:

a) P(7.99 ≤ X ≤ 8.01) = 0.8164

b) P(X ≥ 8.01) = 0.0475.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 8, \sigma = 0.03

(a) Calculate P(7.99 ≤ X ≤ 8.01) when n = 16.

n = 16, so s = \frac{0.03}{4} = 0.0075

This probability is the pvalue of Z when X = 8.01 subtracted by the pvalue of Z when X = 7.99. So

X = 8.01

Z = \frac{X - \mu}{\sigma}

Applying the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.01 - 8}{0.0075}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

X = 7.99

Z = \frac{X - \mu}{s}

Z = \frac{7.99 - 8}{0.0075}

Z = -1.33

Z = -1.33 has a pvalue of 0.0918

0.9082 - 0.0918 = 0.8164

P(7.99 ≤ X ≤ 8.01) = 0.8164

(b) How likely is it that the sample mean diameter exceeds 8.01 when n = 25? P(X ≥ 8.01) =

n = 25, so s = \frac{0.03}{5} = 0.006

This is 1 subtracted by the pvalue of Z when X = 8.01. So

Z = \frac{X - \mu}{s}

Z = \frac{8.01 - 8}{0.006}

Z = 1.67

Z = 1.67 has a pvalue of 0.9525

1 - 0.9525 = 0.0475

P(X ≥ 8.01) = 0.0475.

4 0
3 years ago
How do I find 1/4 of 52
Neporo4naja [7]

Answer:

13

Step-by-step explanation:

1/4 of 52 is actually telling us to multiply 1/4 by 52 over 1.

1/4×52/1

=13

5 0
2 years ago
an official playing field (including end zone) for the indoor football league has a length 39 yd longer than its width. the peri
ch4aika [34]

Answer:

42

Step-by-step explanation:

39+39 = 78

162 - 78 = 2 lengths =84

84/2 = 42

5 0
2 years ago
bookstore ordered 1,528 packs of pens and 1,823 packs of pencils at the prices shown. how much did the bookstore spend on pens?
IgorC [24]
I found that the given prices are $ 4 per pack of pens and $ 3 per pack of penciles.

The question is how much the bookstore spent on pens.

Then you have to multiply the number packs of pens, which is 1,528, times the price per pack pens which is $ 4.

So, the answer is: 1528 packs of pens * $ 4 / pack of pens = $6112.


8 0
3 years ago
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