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2 years ago

Noah is shopping for new socks. He sees many different options. One bag has 12 socks for $9.99, another bag has 20

Mathematics

2 answers:

jasenka [17]2 years ago

5 0

Answer:

Second bag having 20 socks for $ 14.99 is the best deal.

Step-by-step explanation:

To find the best deal, you have to find the unit rate

First bag:

Unit rate = 9.99 ÷ 12 = $ 0.8325

Second bag:

unit rate = 14.99 ÷ 20 = $ 0.7495

Third bag:

Unit rate = 19.99 ÷ 10 = $ 1.999

Second bag having 20 socks for $ 14.99 is the best deal.

TEA [102]2 years ago

4 0

Answer:

the bag with 20 socks for $14.99

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exis [7]

Answer:

Part 1) The length of the longest side of ∆ABC is 4 units

Part 2) The ratio of the area of ∆ABC to the area of ∆DEF is $\frac{1}{100}$

Step-by-step explanation:

Part 1) Find the length of the longest side of ∆ABC

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

The ratio of its perimeters is equal to the scale factor

Let

z ----> the scale factor

x ----> the length of the longest side of ∆ABC

y ----> the length of the longest side of ∆DEF

$z=\frac{x}{y}$

we have

$z=\frac{1}{10}$

$y=40\ units$

substitute

$\frac{1}{10}=\frac{x}{40}$

solve for x

$x=(40)\frac{1}{10}$

$x=4\ units$

therefore

The length of the longest side of ∆ABC is 4 units

Part 2) Find the ratio of the area of ∆ABC to the area of ∆DEF

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of ∆ABC

y ----> the area of ∆DEF

$z^{2}=\frac{x}{y}$

we have

$z=\frac{1}{10}$

$z^2=(\frac{1}{10})^2$

$z^2=\frac{1}{100}$

therefore

The ratio of the area of ∆ABC to the area of ∆DEF is $\frac{1}{100}$

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2 years ago

Please I’ll mark brainliest if you get it right

SpyIntel [72]

C: 24
both of the missing sides are equal to 4

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