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sesenic [268]
3 years ago
13

write a point-slope equation for the line that passes through the point (6,8) and is parallel to the line given by y=-5x+4

Mathematics
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer:

  y -8 = -5(x -6)

Step-by-step explanation:

The point-slope form of the equation for a line is generally written ...

  y -k = m(x -h)

for slope m and point (h, k).

The slope of your parallel line is the same as the slope of the reference line, -5. So your equation is ...

  y -8 = -5(x -6)

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3 years ago
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189

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Answer:

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Step-by-step explanation:

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8 0
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An isosceles triangle ABC has legs of length 24 and a vertex angle that measures 36º . Determine the length of its base, BC , to
iris [78.8K]

Answer: BC=14.8

Step-by-step explanation:

By definition, an Isosceles triangle has two equal sides and its opposite angles are congruent.

Observe the figure attached, where the isosceles triangle is divided into two equal right triangles.

So, in this case you need to use the following Trigonometric Identity:

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In this case, you can identify that:

\alpha =\angle BAD=\angle CAD=18\°\\\\opposite=BD=CD=x\\\\hypotenuse=AB=AC=24

Substituting values, and solving for "x", you get:

sin(18\°)=\frac{x}{24}\\\\24*sin(18\°)=x\\\\x=7.416

Therefore, the length of BC rounded to nearest tenth, is:

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