Answer:
19.4 %
Step-by-step explanation:
The formula for<em> return on assets</em> (ROA) is
ROA = Net income /Total assets × 100 %
Since assets vary, we use the <em>average</em> of the total assets over the period.
<em>Calculate the average total assets</em>
At beginning of year, total assets = $263 000
At end of year, total assets = $313 000
Average = (313 000 + 263 000)/2
Average = 576 000/2
Average = $288 000
===============
<em>Calculate the ROA</em>
Net income = $56 000
ROA = 56 000/288 000 × 100 %
ROA = 0.194 × 100 %
ROA = 19.4 %
The company’s return on assets is 19.4 %.
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r}\\\\ -------------------------------\\\\ (x-3)^2+(y+7)^2=64\implies [x-\stackrel{h}{3}]^2+[y-(\stackrel{k}{-7})]^2=\stackrel{r}{8^2} \\\\\\ center~(3,-7)\qquad radius=8](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%0A%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%0A%5Cqquad%20%0Acenter~~%28%5Cstackrel%7B%7D%7B%20h%7D%2C%5Cstackrel%7B%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%20%0Aradius%3D%5Cstackrel%7B%7D%7B%20r%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%28x-3%29%5E2%2B%28y%2B7%29%5E2%3D64%5Cimplies%20%5Bx-%5Cstackrel%7Bh%7D%7B3%7D%5D%5E2%2B%5By-%28%5Cstackrel%7Bk%7D%7B-7%7D%29%5D%5E2%3D%5Cstackrel%7Br%7D%7B8%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Acenter~%283%2C-7%29%5Cqquad%20radius%3D8)
so, the broadcast location and range is more or less like the picture below.
Answer:
Final answer is approx 6.644 years.
Step-by-step explanation:
Given that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles is 16% every year and that of cars is 25% every year.
So we can use growth formula:

Then we get equation for motorcycles and cars as:


Now we need to find about when the sale of cars will be more than the sale of motorcycles. So we get:








Hence final answer is approx 6.644 years.
Answer:
im not good at this but would it be answer c?
Step-by-step explanation:
1. Decrease
2.Increase
3.Decrease
4.Increase
5.Decrease
6.Decrease