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Zarrin [17]
2 years ago
11

Please help me answer question 6/11

Mathematics
1 answer:
Law Incorporation [45]2 years ago
7 0

The value of a₄₁ mean the expression in 4th row and 1st column will be 2. Then the correct option is B.

The complete question is attached below.

<h3>What is the matrix?</h3>

A matrix is a specific arrangement of items, particularly numbers. A matrix is a row-and-column mathematical structure. The \rm a_{ij} element in a matrix, such as M, refers to the i-th row and j-th column element.

The matrix is given below.

\begin{bmatrix}  1&3&8&5&\\ 5&4&6&2\\6&7&1&8\\2&9&3&7&\\\end{bmatrix}

Then the value of a₄₁ mean the expression in 4th row and 1st column will be 2.

Then the correct option is B.

More about the matrix link is given below.

brainly.com/question/9967572

#SPJ1

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A company has 50 employees all working in the same building.
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Yes it did because 90% of fifty is 45 (50 divided by 10 x 5) and the graph shows that 46 employees left the building within a minute
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How many positive integers $n$ from 1 to 5000 satisfy the congruence $n \equiv 5 \pmod{12}$?
irga5000 [103]
The equivalence n \equiv 5 \pmod{12}

means that n-5 is a multiple of 12.

that is

n-5=12k, for some integer k

and so

n=12k+5


for k=-1, n=-12+5=-7

for k= 0, n=0+5=5 (the first positive integer n, is for k=0)


we solve 5000=12k+5 to find the last k

12k=5000-5=4995

k=4995/12=416.25

so check k = 415, 416, 417 to be sure we have the right k:

n=12k+5=12*415+5=4985

n=12k+5=12*416+5=4997

n=12k+5=12*417+5=5009


The last k which produces n<5000 is 416


For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,

thus there are 417 integers n satisfying the congruence.


Answer: 417

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3 years ago
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alukav5142 [94]

Answer:

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Step-by-step explanation:

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Read 2 more answers
A- y= -3/2x+8<br> B- y=3/2x+5<br> C- y=2/3x+8<br> D- y=-2/3x+5
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Answer:

I think the right answer is B.

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A

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