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4 years ago

Which ordered pair is a solution of the equation y = 4x - 3?

Mathematics

1 answer:

Greeley [361]4 years ago

3 0

Answer:

(0,-3)

(1,1)

(2,5)

Step-by-step explanation:

They're all correct. it doesn't matter which one you choose.

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So idk what 4.25 is rounded to the neatest 10 can you help?

s344n2d4d5 [400]

Answer:not the answer person but wouldn't it be 4 cause it's not more then half of the number lol.

Step-by-step explanation:

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3 years ago

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What's the group factor for 6×(2×2) and the product

Bas_tet [7]

Simplify the expression.
24

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4 years ago

if there were 36 students and nine of them have freckles what is the ratio with the students who do have freckles

Nikitich [7]

The ratio would be if it was not reduced, 9:36. If it was reduced it would be 1:4

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4 years ago

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A cube has side length x. One side of the cube is increased by 4 inches, and another side is doubled. The volume of the new rect

AfilCa [17]

Let

x-------> the length side of the original cube

we have

$2x^{3} +8x=450\\2x^{3}=450-8x$

Divide by $2$ both sides

$x^{3}=225-4x$

The system of equations is equal to

$y=x^{3}$ --------> equation $1$

$y=225-4x$ --------> equation $2$

using a graphing tool

see the attached figure

we know that

the solution of the system of equations is the intersection both graphs

therefore

the solution is

$x=5.86\ in$

therefore

<u>the answer is</u>

$5.86\ inches$

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4 years ago

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U can start immediately I already got the answer I just need to see if i got it right and understand

umka21 [38]

ANSWER

80 units²

EXPLANATION

One way to solve this is to find the area of the blue square and the subtract the areas of the red triangles:

The blue square is 12 units long by 12 units wide. Its area is:

$A_{\text{square}}=12\times12=144$

Then, the area of the big triangle, which has a base 12 units long and a height of 10 units, is:

$A_{\text{traingle}1}=\frac{12\times10}{2}=\frac{120}{2}=60$

The smaller triangle has a base of 4 units and a heigth of 2 units. Its area is:

$A_{\text{triangle}2}=\frac{4\times2}{2}=\frac{8}{2}=4$

So the total area of the figure is:

$\begin{gathered} A=A_{\text{square}}-A_{triangle1}-A_{triangle2} \\ A=144-60-4 \\ A=80 \end{gathered}$

8 0

2 years ago