X+19=13 Find the value of x.

2 answers:

7 0

Solution
X+19=13

1) Subtract 19 from both sides
X=13−19

2) Simplify 13−19 to −6
X=−6

CHECK ANSWER

X+19=13

1) Let X=−6
−6+19=13

2 Simplify −6+19 to 13
13=13

Oliga [24]4 years ago

4 0

To find the value of x we need to use the INVERSE OPERATION of addition which is subtraction. Then we will check our work. lets do it:-

x + 19 = 13
x = ?
13 - 19 = x
13 - 19 = -6
x = - 6

CHECK OUR WORK:-

x + 19 = 13
x = -6
-6 + 19 = 13
We were RIGHT!!

So, x = -6

Hope I helped ya!! xD

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What is a simple way to solve for the sum and difference of 2 cubes? For example, 27+64<img src="https://tex.z-dn.net/?f=x%5E3"

salantis [7]

Answer:

(3 + 4x)(9 - 12x + 16x²) = 0

(4m - 1)(16m² + 4m + 1) = 0

Step-by-step explanation:

Here we have to solve the sum of two cubes which is $27 + 64x^{3}$

Now, the equation is $27 + 64x^{3} = 0$

⇒ 3³ + (4x)³ = 0

⇒ (3 + 4x)[3² - 3(4x) + (4x)²] = 0

⇒ (3 + 4x)(9 - 12x + 16x²) = 0

So, (3 + 4x) = 0 or (9 - 12x + 16x²) = 0

Therefore, from the above two relation we can solve for x.

One root will be $- \frac{3}{4}$ and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.

Again, we have to solve the difference of two cubes which is $64m^{3} - 1$

Now, the equation is $64m^{3} - 1 = 0$

⇒ (4m)³ - 1³ = 0

⇒ (4m - 1)[(4m)² + 4m(1) + 1²] = 0

⇒ (4m - 1)(16m² + 4m + 1) = 0

So, (4m - 1) = 0 or (16m² + 4m + 1) = 0

Therefore, from the above two relation we can solve for m.

One root will be $\frac{1}{4}$ and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation. (Answer)