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2 years ago

5

If you cut a 3 3/4 ft. length of wire into pieces that 1/4 ft. long, how many pieces of wire will you have?

2 answers:

lukranit [14]2 years ago

6 0

Answer:

I think it would be 15

Step-by-step explanation:

Snezhnost [94]2 years ago

6 0

15.

3 3/4 feet and the length is 1/4 long if this helped pls mark me the brainiest?

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Given A(-1,4) B(1,5) and C(-5,3) which coordinate will make AB parallel to CD?

Solnce55 [7]

I think b not sure tho

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3 years ago

Given f(x) = x^2 - 5x, find f(x-3)

Hoochie [10]

Answer:

f(x-3)= x^2 -11x +24

Step-by-step explanation:

We want to find an equivalent expression for f(x-3)

To do this, we can simply substitute every 'x' variable in f(x) by 'x-3'

Therefore f(x-3)= (x-3)^2 -5*(x-3)

Lets re arrange the expression by grouping terms.

f(x-3)=x^2 - 6x +9 -5x + 15

f(x-3)= x^2 -11x +24

3 0

3 years ago

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Simplify the expression: 5(x + 2) > 50

kondor19780726 [428]

Answer:

x >8

Step-by-step explanation:

6 0

3 years ago

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2 years ago