How to solve a=9y+3yx
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To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:
<u>Rectangle (a)</u>
<u>Rectangle (b)</u>
<u>Rectangle (c)</u>
<u>Rectangle (d)</u>
Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
Read more about areas of rectangles at:
Since the bottom shape is a semi-circle, the 3yd is the radius making the triangle's area 7 x 3 / 2 = 10.5
The semi-circle's area is
/2 = 14.14
Combined, you get an area of 10.5 + 14.14 = 24.64
The semi-circle's area is
Combined, you get an area of 10.5 + 14.14 = 24.64