Answer:
AC = 12 cm
Step-by-step explanation:
AB=9 centimeters, you figure out what times what is 9. in this case, it is 3 for A and B. Then you go to BC=12 and 3 for B and 4 for C making it 12 So AC would equal 3x4.
Answer:
- <u>3 </u><u>and</u><u> 17</u> are required integers
Step-by-step explanation:
- Let one integer be x
- And other integer be y
x = 4y + 5
xy = 51
<u>According to </u><u>question </u><u>:</u>
➞ (4y + 5)y = 51
➞ 4y² + 5y = 51
➞ 4y² + 5y - 51 = 0
➞ 4y² + 17y - 12y - 51 = 0
➞ y (4y + 17) - 3(4y + 17) = 0
➞ (y - 3)(4y - 17) = 0
➞ y - 3 = 0
➞ <u>y = 3</u>
Hence,
➞ <u>y = 3</u>
➞ x = 4y + 5
➞ x = 4 (3) + 5
➞ x = 12 + 5
➞<u> </u><u>x = 17</u>
∴ The required integers are <u>3 and 17</u>
Answer:
{t|60 <= t <= 85}
Step-by-step explanation:
The temperatures were measures at different times, but does not stop the values being real numbers (i.e. not discrete, or integer values).
So the range of the function is the set of all values between the minimum and maximum measured during the measuring interval (domain) of hours two and twenty-two.
The minimum value = 60F
The maximum value = 85F
So the interval of the range is [60,85], in interval notation.
In set-builder notation, it is
{t|60 <= t <= 85}
The shape looks like a box with a chunk taken out of it. So, to find the volume of the shape, let us find the volume of the hypothetical "perfect" box and then subtract the volume of the chunk.
Volume of the box = 15x6x12 = 1080 cm³
Volume of the chunk = 10x6x4 = 240 cm³
Volume of weird shape = 1080-240 = 840 cm³
Answer: 840 cm³
