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Nina [5.8K]
3 years ago
11

How can I get better in mathematics?

Mathematics
1 answer:
aliya0001 [1]3 years ago
8 0

Answer:

STUDY OR TUTOURStep-by-step explanation:

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Sue has a picture that is 7 1/2 inches across and 8 inches long. She wants to put a border that is 1 1/4 around the picture. Wha
Hitman42 [59]
Find the perimeter of a picture first.

width = 7 1/2 = 15/2 in

length = 8 in

perimeter = 2(width) + 2(length)

p = 2(15/2) + 2(8)

p = 15 + 16

p = 31 in

next, find the perimeter of border.

p = 4(1 1/4)

p = 4(5/4)

p = 5 in

perimeter of picture with border = 31 + 5 = 36 in
6 0
3 years ago
Compute the value of the discriminant and give the number of real solutions of the quadratic equation. -9x to the second power-6
Step2247 [10]
Answer:
discriminant=0
Number of real solutions=1


Step-by-step explanation:

Given the equation:
-9x^2-6x-1=0
Let a: coefficient of x^2
Let b: coefficient of x
Let c: constant
a=-9
b=-6
c=-1
The formula of the discriminant is given by:
discriminant= b^2 - 4ac
discriminant= (-6)^2 - 4(-9)(-1)
= 36 - 36 = 0
We know that:
If discriminant<0 then the equation has no real root
If discriminant=0 the equation has one real root
If discriminant>0 the equation has 2 real roots

Here we got discriminant=0 so the quadratic equation has 1 real root.
8 0
2 years ago
Please solve i and ii for me
KengaRu [80]

If you know the derivative f'(x) of some function f(x), you can tell exactly who f(x) is, up to an additive, constant term. In fact, knowing f'(x), you have

\displaystyle \int f'(x) = f(x)+c

In your case, we have

\dfrac{d}{dx} \sqrt{x+3} = \dfrac{1}{2\sqrt{x+3}}

So, the integral is almost immediate:

\displaystyle\int \dfrac{2}{\sqrt{x+3}} = \int \dfrac{4}{2\sqrt{x+3}} = 4\int\dfrac{1}{2\sqrt{x+3}} = 4\sqrt{x+3}+c

So, up to some constant additive term, our function is 4\sqrt{x+3}+c

To fix this constant, we know that the function passes through the point (6,10), so we have

f(6) = 4\sqrt{6+3}+c = 4\sqrt{9}+c=12+c=10 \iff c=-2

And so our function is 4\sqrt{x+3}-2

If we want to know when this function equals 6, we simply have to ask f(x)=6 and solve for x, so we have

4\sqrt{x+3}-2=6 \iff 4\sqrt{x+3} = 8 \iff \sqrt{x+3} = 2 \iff x+3=4 \iff x = 1

5 0
3 years ago
There are 17 goats in the barn 8 goats goes outside how many goats are still in the barn
andreyandreev [35.5K]
9 goats are still in the barn
3 0
3 years ago
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What is all the answers to a 2 × problem​
nalin [4]
Double the number like 2 x5 would be 5+5
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3 years ago
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