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guapka [62]
3 years ago
7

(5 + 4 – 2) × (–2) = ?

Mathematics
1 answer:
Debora [2.8K]3 years ago
5 0

Answer:

B. -14

Step-by-step explanation:

(5 + 4 – 2) × (–2)

7x(-2)

=-14

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FromTheMoon [43]

9514 1404 393

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  5

Step-by-step explanation:

To solve the inequality, we can do the following.

  4.55g + 8.50 ≤ 35 . . . given

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3 years ago
Write the equation of a line that is perpendicular to y=-0.3x+6 and that passes through the point (3,-8)
MariettaO [177]
Hey there!

First, let's look at what perpendicular means. Imagine a cross, where there's all 90 degree angles. That's exactly what we're talking about when we say perpendicular. The given equation is in slope-intercept form, where we have:

y = mx + b
where m is the slope and b is the y-intercept.

When we're writing an equation with a perpendicular slope, we use the negative reciprocal of the given slope. Thus, we can make 0.3 1/3, and take the reciprocal to make 3, and make it negative 3 as it's the negative reciprocal. Now, we know we have a line with the slope of -3 and goes through (-3, 8). We can use the x and y values in this set of points, along with the slope, to create an equation to solve for b. That gives us:

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17 = b

Now, since we have slope and y-intercept, we can write our equation as:

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5 0
3 years ago
Read 2 more answers
X^2-14x-4=0, solve by completing the square
REY [17]
The answer is: x = 7 - √53      or      x = 7 + √53

The general quadratic equation is: ax² + bx + c  = 0.
But, by completing the square we turn it into: a(x + d)² + e = 0, where:<span>
d = b/2a
e = c - b²/4a
Our quadratic equation is x² - 14x -4 = 0, which is after rearrangement:
So, a = 1, b = -14, c = -4
Let's first calculate d and e:
d = b/2a = -14/2*1 = -14/2 = -7
e = c - b²/4a = -4 - (-14)</span>²/4*1 = -4 - 196/4 = -4 - 49 = -53<span>
By completing the square we have:
a(x + d)² + e = 0

1(x + (-7))</span>² + (-53) = 0
(x - 7)² - 53 = 0
(x - 7)² = 53
x - 7 = +/-√53
x = 7 +/- √53

Therefore, the solutions are:
x = 7 - √53
or
x = 7 + √53
4 0
3 years ago
Read 2 more answers
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