Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate, 
= 6 boats per hour.
Service rate, 
= 10 boats per hour.
Probability of zero boats in the system,![\mathrm{PO}=1 /\{[(1 / 0 !) \times(6 / 10) 0+(1 / 1 !) \times(6 / 10) 1]+[(6 / 10) 2 /(2 ! \times(1-(6 /(2 \times 10)))]\}](https://tex.z-dn.net/?f=%5Cmathrm%7BPO%7D%3D1%20%2F%5C%7B%5B%281%20%2F%200%20%21%29%20%5Ctimes%286%20%2F%2010%29%200%2B%281%20%2F%201%20%21%29%20%5Ctimes%286%20%2F%2010%29%201%5D%2B%5B%286%20%2F%2010%29%202%20%2F%282%20%21%20%5Ctimes%281-%286%20%2F%282%20%5Ctimes%2010%29%29%29%5D%5C%7D)
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
= ![[\{6 \times 10 \times(6 / 10) 2\} /\{(2-1) ! \times((2 \times 10)-6) 2\}] \times 0.5385](https://tex.z-dn.net/?f=%5B%5C%7B6%20%5Ctimes%2010%20%5Ctimes%286%20%2F%2010%29%202%5C%7D%20%2F%5C%7B%282-1%29%20%21%20%5Ctimes%28%282%20%5Ctimes%2010%29-6%29%202%5C%7D%5D%20%5Ctimes%200.5385)
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.
Answer:
<u>inocme statment:</u>
wages expense: understate
<u>net income</u> overstate
<u>blanace sheet</u>
wages payable: understate
Retained Earnings: overstate
Explanation:
If the adjusting entry is not made, then the expenses will be lower than it should.
Thereofre the net income will be overstate as there are more expenses but weren't recorded.
the balance sheet will not represent accurate the liabilities as there is wages payable which are not recorded.
also, in the blaance sheet the Retained Earnings account will be overstate as it include the net income which is overstate.
Answer:
Average rate of return = 14
%
Explanation:
Average rate of return = Annual average return/ Average Investment
Average investment =( Initial investment + scrap value)/2
Average investment = 138,000 + 12,000/2 =75,000
Average annual return = Savings in cost - energy cost - depreciation
Depreciation = (initial cost - scrap value)/2= (138,000 - 12,000)/2= 12600
Average annual return = 29,780-6,680-12600= 10500
Average rate of return = 10,500/75,000 × 100= 14
%
Average rate of return = 14
%
<span>The physical hardware and is responsible for the delivery of signals from the source to the destination over a physical communication platform is the data link. The data link allows the layer to communicate in a way that helps everything fall into place.</span>
<span>This is an example of adapting to a new environment. It is an improved function that is produced by natural selection. They reproduce more often in a new environment because they have the necessary food or climate or both to be able to sustain population growth.</span>
