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adelina 88 [10]
3 years ago
7

A carton has a length of fraction 2 and 2 over 3 feet, width of fraction 1 and 1 over 8 feet, and height of fraction 1 and 1 ove

r 5 feet. What is the volume of the carton?
fraction 3 and 3 over 5 cubic feet
fraction 4 and 1 over 5 cubic feet
fraction 5 and 2 over 5 cubic feet
fraction 7 and 1 over 5 cubic feet
Mathematics
2 answers:
telo118 [61]3 years ago
6 0

Answer:

fraction 3 and 3 over 5 cubic feet

Step-by-step explanation

Pachacha [2.7K]3 years ago
4 0

Answer:

  • fraction 3 and 3 over 5 cubic feet

Step-by-step explanation:

Volume formula  V= lwh

<u>Given</u>

  • l = 2 2/3 = 8/3 ft
  • w = 1 1/8 = 9/8 ft
  • h = 1 1/5 = 6/5 ft

<u>Volume is:</u>

  • V = 8/3*9/8*6/5 =18/5 = 3 3/5 ft³

Correct option is A

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Answer:

20 squared + 35 squared = d squared

Step-by-step explanation:

The Pythagorean theorem a^2+b^2=c^2

4 0
3 years ago
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A line contains the points (3,9) and (-1,1) what is the equation of the line?
kirza4 [7]
To find the equation of a line using two given set of points, you must first find slope. To do so, we must use the slope formula:
y2 - y1 / x2 - x1 

In this case:
1 - 9 / -1 - 3 = -8 / -4 
- 8 / -4 = 2 (simplified) 

Now we can use the point-slope formula:
y - y1 = m(x - x1) 

y - 1 = 2(x + 1 )
y - 1 = 2x + 2
y = 2x + 3

In order to make 3x - y = 6 in slope intercept form, we must isolate y.

- y = -3x + 6
Note: y cannot be negative, so we'll multiply both sides by -1 
( -1 ) - y = - 3x + 6 ( -1 ) = y = 3x -6
6 0
4 years ago
Read 2 more answers
Please help me with these three ​
anyanavicka [17]
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15) perpendicular because the gradients multiply together to get -1
8 0
3 years ago
Which equation demonstrates the additive identity property?
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It's the first one (7+4i)+(7-4i)=14
6 0
3 years ago
Find the slope of the tangent line to the polar curve r = \sin (6 \theta) at \theta = \frac{\pi}{12}.
ra1l [238]

By converting into parametric equations,

<span>{<span><span>x<span>(θ)</span>=r<span>(θ)</span><span>cosθ</span>=<span>cos2</span>θ<span>cosθ</span></span><span>y<span>(θ)</span>=r<span>(θ)</span><span>sinθ</span>=<span>cos2</span>θ<span>sinθ</span></span></span></span>

By Product Rule,

<span>x'<span>(θ)</span>=−<span>sin2</span>θ<span>cosθ</span>−<span>cos2</span>θ<span>sinθ</span></span>

<span>x'<span>(<span>π2</span>)</span>=−<span>sin<span>(π)</span></span><span>cos<span>(<span>π2</span>)</span></span>−<span>cos<span>(π)</span></span><span>sin<span>(<span>π2</span>)</span></span>=1</span>

<span>y'<span>(θ)</span>=−<span>sin2</span>θ<span>sinθ</span>+<span>cos2</span>θ<span>cosθ</span></span>

<span>y'<span>(<span>π2</span>)</span>=−<span>sin<span>(π)</span></span><span>sin<span>(<span>π2</span>)</span></span>+<span>cos<span>(π)</span></span><span>cos<span>(<span>π2</span>)</span></span>=0</span>

So, the slope m of the curve can be found by

<span>m=<span><span>dy</span><span>dx</span></span><span>∣<span>θ=<span>π2</span></span></span>=<span><span>y'<span>(<span>π2</span>)</span></span><span>x'<span>(<span>π2</span>)</span></span></span>=<span>01</span>=0</span>

I hope that this was helpful.

4 0
4 years ago
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