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Sveta_85 [38]
3 years ago
10

8 1/2 + 7 2/3 + 4 1/2

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
5 0

Answer:

62/3 is the answer

hope this helps! :)

Step-by-step explanation:

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Need help please asap due 5:30​
notsponge [240]

Answer:

5 30 is my guess

Step-by-step explanation:

3 0
3 years ago
Jimmy has a piece of string that is 6 3/4 inches long, and Sam has a piece of string that is 7 1/2 inches long.
mafiozo [28]

Answer:

3/4 inches

Step-by-step explanation:

Subtract Jimmys string length from Sam's string length

7 1/2 - 6 3/4

Get a common denominator of 4

7 1/2*2/2 - 6 3/4

7 2/4 - 6 3/4

Borrow 1 ( or 4/4) from the 7

6 4/4 + 2/4 - 6 3/4

6 6/4 - 6 3/4

3/4

6 0
3 years ago
Read 2 more answers
Lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. a bank conducts inter
Otrada [13]
Part A:

Given that lie <span>detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector correctly determined that a selected person is saying the truth has a probability of 0.85
Thus p = 0.85

Thus, the probability that </span>the lie detector will conclude that all 15 are telling the truth if <span>all 15 applicants tell the truth is given by:

</span>P(X)={ ^nC_xp^xq^{n-x}} \\  \\ \Rightarrow P(15)={ ^{15}C_{15}(0.85)^{15}(0.15)^0} \\  \\ =1\times0.0874\times1=0.0874
<span>

</span>Part B:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15

Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:

P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(X\geq1)=1-P(0) \\  \\ =1-{ ^{15}C_0(0.15)^0(0.85)^{15}} \\ \\ =1-1\times1\times0.0874=1-0.0874 \\  \\ =0.9126


Part C:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The mean is given by:

\mu=npq \\  \\ =15\times0.15\times0.85 \\  \\ =1.9125


Part D:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The <span>probability that the number of truthful applicants classified as liars is greater than the mean is given by:

</span>P(X\ \textgreater \ \mu)=P(X\ \textgreater \ 1.9125) \\  \\ 1-[P(0)+P(1)]
<span>
</span>P(1)={ ^{15}C_1(0.15)^1(0.85)^{14}} \\  \\ =15\times0.15\times0.1028=0.2312<span>
</span>
8 0
3 years ago
IS THIS CORRECT ???????
Shkiper50 [21]

Answer:

yes

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
(6x+2)^2=36x^2+Bx+4 How Would You Answer That. I'm Not That Good At Algebra.
Verizon [17]

Let's multiply out the equation 6x+2 times 6x+2 using the square. Draw a 2 by 2 bow and put the equation across the bottom and verically. Multiply across to get this. 6x times 6x =36x^2 6x times two =12x do it again and get 12x. 2*2=4. That means x would equal 24.

8 0
3 years ago
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