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Zigmanuir [339]
3 years ago
12

Express the following as ratio 15 minutes to 3 hours​

Mathematics
1 answer:
mario62 [17]3 years ago
7 0

Answer:

15 mintues/ 3 hours

Step-by-step explanation:

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Circumference (rounding)
LUCKY_DIMON [66]

Answer:

19.5

Step-by-step explanation:

Circumference is radius multiplied by 2, then multiplied by pi.

3.1 × 2= 6.2

6.2 × π= 19.477 ≈ 19.5

π also equals 3.14

4 0
3 years ago
Read 2 more answers
A bag contains coins of rupees 2 Rupees 1 and 50 paise, in ratio of 1 is to 2 is to 4. if the total amount is rupees 72 find how
BabaBlast [244]

Answer:

<u>Final </u><u>answer </u><u>-</u>

number \: of \: 50 \: paise \: coins \: in \: the \: bag = 4x \\ \dashrightarrow{4 \times 12 = 48 \: coins}

hope helpful :D

4 0
2 years ago
What's is an equation of the line that passes through the point(-3,-1) and is perpendicular to the line x-2y=6
katrin2010 [14]

Answer:

y+1=-2(x+3)

Step-by-step explanation:

Slope is negative reciprocal when two lines are perpendicular

m1=1/2 therefore m2=-2

The equation of the line in point-slope form is given as

y-y_1=m_2(x-x_1)

Here m=-2 and (x1, y1)=(-3, -1)

Therefore,

y+1=-2(x+3)

6 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
The sum of two numbers is with a ratio of 15:10 .find the larger number
Naddik [55]
With ratio to get the same ratio but bigger or smaller numbers you should double the ratio or half it. Dont know if this was any help :)
3 0
3 years ago
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