<h2>
Answer:</h2>
The determinant of the given matrix is:
a) -42
<h2>
Step-by-step explanation:</h2>
We are given a matrix let A as:
![A=\left[\begin{array}{ccc}5&4\\8&-2\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%264%5C%5C8%26-2%5Cend%7Barray%7D%5Cright%5D)
Determinant of a matrix--
The determinant of a 2×2 i.e. a square matrix of order 2 is calculated as follows:
If:
![A=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
then the determinant denoted by det(A) or |A| is given by:

Here a=5, b=4 , c=8 and d= -2
Hence, the determinant is given by:

The correct answer is: Option: a)