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trasher [3.6K]
3 years ago
10

-5(2b + 7) + b < -b - 11

Mathematics
1 answer:
Stells [14]3 years ago
8 0
<span><span>-5(2b+7) + b < -b - 11</span>
<span>-10b - 35 + b < -b - 11

- 10b + b - 35 < -b - 11

-9b - 35 < -b - 11

- 9b + b < - 11 + 35 

-8b < 24

</span></span>\frac{-8b}{-8} \ \textless \  \frac{24}{-8}
<span><span>
b < -3

Have a nice days.........</span></span>
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HELP ME QUICK PLEASEEEE solve for x: 2/x-2+7/x^2-4=5/x
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\displaystyle\\\\\frac{2}{x-2}+\frac{7}{x^2-4}=\frac{5}{x}\\\\\frac{^{x+2)}2~~~~~}{x-2}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2(x+2)}{(x-2)(x+2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2x+4+7}{x^2-4}=\frac{5}{x}\\\\\frac{2x+11}{x^2-4}=\frac{5}{x}\\\\5(x^2-4)=x(2x+11)\\\\5x^2-20=2x^2+11x\\\\5x^2-2x^2 -11x-20=0


\displaystyle\\3x^2-11x-20=0\\\\x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{11\pm\sqrt{121+4\cdot3\cdot20}}{2\cdot3}=\\\\=\frac{11\pm\sqrt{121+240}}{6}=\frac{11\pm\sqrt{361 }}{6}=\frac{11\pm19}{6}\\\\x_1=\frac{11-19}{6}=\frac{-8}{6}\\\\\boxed{\bf x_1=-\frac{4}{3}}\\\\x_2=\frac{11+19}{6}=\frac{30}{6}\\\\\boxed{\bf x_2=5}




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\textsf{Hey there!}

\mathsf{\star \ The\ sum\ of\ a\ number\ \&\  forty-six}

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\bullet \ \textsf{The word \bf{\underline{SUM}}}\textsf{\ means\ add/addition}}

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