The weights are within 2 standard deviations of the mean are 8.9 lbs, 9.5 lbs and 10.4 lbs
<h3>How to determine the weights?</h3>
The given parameters are:
- Mean, μ = 9.5
- Standard deviation, σ = 0.5
The weights within 2 standard deviation is represented as:
μ - 2σ ≤ x ≤ μ + 2σ
Substitute known values
9.5 - 2(0.5) ≤ x ≤ 9.5 + 2(0.5)
Evaluate the product
9.5 - 1 ≤ x ≤ 9.5 + 1
Evaluate the sum
8.5 ≤ x ≤ 10.5
This means that the weights are between 8.5 and 10.5 (inclusive)
Hence, the weights are within 2 standard deviations of the mean are 8.9 lbs, 9.5 lbs and 10.4 lbs
Read more about standard deviation at:
brainly.com/question/11743583
Answer is C because there is a constant rate of change (+2) in the y-values. As x increases by 1, y increases by 2.
Answer:
What??
Step-by-step explanation:
My answer to the problem is as follows:
Expressed as an absolute value.
<span>
The difference between the actual length, x, and the specification, 43.6, can be no more than 0.1 </span>
<span>
|x - 43.6| ≤ 0.1 <–––––
</span>
<span>The 43.6 is the target length, and the tolerance of 0.1 is how far off from the target is acceptable.</span>
Answer:
f(x)=750-15t
Step-by-step explanation:
He starts off at 750 meters, and he decends 15 meters psr minute
